Answer:
it would be letter E. near oceanic ridges
Explanation:
new ocean crust is formed at the mid ocean ridges
Answer:
the distance between the submarine and the ocean floor is 11,250 m
Explanation:
Given;
speed of the wave, v = 1500 m/s
time of motion of the wave, t = 15 s
The time taken to receive the echo is calculated as;
![time \ of \ motion \ (t) = \frac{total \ distance }{speed \ of \ wave} = \frac{2d}{v} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{1500 \times 15}{2} \\\\d = 11,250 \ m](https://tex.z-dn.net/?f=time%20%5C%20of%20%5C%20motion%20%5C%20%28t%29%20%3D%20%5Cfrac%7Btotal%20%5C%20distance%20%7D%7Bspeed%20%5C%20of%20%5C%20wave%7D%20%3D%20%5Cfrac%7B2d%7D%7Bv%7D%20%20%5C%5C%5C%5C2d%20%3D%20vt%5C%5C%5C%5Cd%20%3D%20%5Cfrac%7Bvt%7D%7B2%7D%20%5C%5C%5C%5Cd%20%3D%20%5Cfrac%7B1500%20%5Ctimes%2015%7D%7B2%7D%20%5C%5C%5C%5Cd%20%3D%2011%2C250%20%5C%20m)
Therefore, the distance between the submarine and the ocean floor is 11,250 m
maximum allowed value of the speed in roller coaster is given as
![v = 20 m/s](https://tex.z-dn.net/?f=v%20%3D%2020%20m%2Fs)
now from kinematics we can say
![v^2 - v_i^2 = 2 a s](https://tex.z-dn.net/?f=v%5E2%20-%20v_i%5E2%20%3D%202%20a%20s)
here initial speed will be
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
acceleration is due to gravity
![a = 9.8 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.8%20m%2Fs%5E2)
now we can use this to find the height
![20^2 - 0^2 = 2 * 9.8* h](https://tex.z-dn.net/?f=20%5E2%20-%200%5E2%20%3D%202%20%2A%209.8%2A%20h)
![400 = 19.6 *h](https://tex.z-dn.net/?f=400%20%3D%2019.6%20%2Ah)
![h = 20.4 m](https://tex.z-dn.net/?f=h%20%3D%2020.4%20m)
so maximum allowed height will be 20.4 m
Answer:
Average speed equals distance / time
380 / 40 = 9.5 m/s.
Explanation: