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crimeas [40]
3 years ago
8

3. The expression 0.62 x10^3 is equivalent to...

Physics
2 answers:
Korolek [52]3 years ago
5 0

\\ \sf\longmapsto 0.62\times 10^3

\\ \sf\longmapsto 62\times 10^{-2}\times 10^3

\\ \sf\longmapsto 62\times 10^{-2+3}

\\ \sf\longmapsto 62\times 10^1

\\ \sf\longmapsto 62\times 10

\\ \sf\longmapsto 620

Nitella [24]3 years ago
5 0

Answer:

620

Explanation:

0.62*1000=620

10^3= 10*10*10=1,000

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the refractive index of cooking oil is 1.47, and the refractive index of water is 1.33. A thick layer of cooking oil is floating
VARVARA [1.3K]
When light travels from a medium with higher refractive index to a medium with lower refractive index, there is a critical angle after which all the light is reflected (so, there is no refraction).

The value of this critical angle can be derived by Snell's law, and it is equal to
\theta_C = \arcsin ( \frac{n_2}{n_1} )
where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.

In our problem, n1=1.47 and n2=1.33, so the critical angle is
\theta_C = \arcsin( \frac{1.33}{1.47} )=\arcsin (0.91)=65^{\circ}
4 0
3 years ago
Kellie found a sample of a pure element. She carefully studied the sample and made a list of its properties.
aivan3 [116]
1. (C.) -Si- is silicone which at room temp is a solid and it's a hard crystalline Brittle rock basically...

2. And it will Be D. NOT C... i can't stand user's who throw out answers for free points.... 
3 0
3 years ago
Carbon dioxide in the blood is removed from the body through the A. kidneys B. lungs C. mouth D. skin​
natka813 [3]

Answer:

<h2>C) Mouth</h2>

Explanation:

<h2>When we inhale air, it contains oxygen. The lungs take in oxygen and the heart and the other body parts use it.</h2><h2>Carbon dioxide is removed from the blood mouth when we exhale.</h2>
8 0
3 years ago
A plane accelerates from 25 m/s to a velocity of 80 m/s in a time of 5 seconds. What
Natali [406]

Answer:

-7

Explanation:

-7 because -7 said so

6 0
3 years ago
A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
Jlenok [28]

Answer:

14.36 N

Explanation:

T_{1} = Tension in string 1

T_{2} = Tension in string 2

m_b = mass of the bar = 2.7 kg

W_b = weight of the bar

weight of the bar is given as

W_b = m_{b} g = (2.7) (9.8) = 26.46N

m_m = mass of the bar = 1.35 kg

W_m = weight of the monkey

weight of the monkey is given as

W_m = m_{m} g = (1.35) (9.8) = 13.23N

Using equilibrium of torque about left end

W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33 N

Using equilibrium of force in vertical direction

T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36 N

7 0
3 years ago
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