Force equals mass*acceleration
F = ma
Given m = 54.87 kg, a = 9.8 m/s^2
F = (54.87)(9.8)
F = 537.726
F = 538 N
A force of al least 538 Newtons is required to move the object.
The distance is 30 km and the displacement is 22.4 km North East
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Answer: Hello! Here your answer......
Force = 10.244 Newtons
b) No of oscillations = 0.88
Explanation:
Since the block executes SHM we can write it's position as function of time as
ω is the natural frequency of the system
A is the amplitude of the system
Thus accleration of the block
Thus using the given values at t= 3.50 sec we can calculate the acceleration as
thus force can be calculated using newtons second law as
b)
Now no of oscillations can be obtained as
no of oscillations in 3.50 seconds = 3.50/3.976 = 0.88
Hope this helps! (Brainly)♥
There are no accurate statements at all on that list.
