Knee sprains can be classified into three grades, depending on the amount of damage: Grade 1: a few fibres (less than 10%) are damaged/torn. Usually heals naturally. Grade 2: more fibres are torn but the ligament is still intact. Grade 3: the ligament is ruptured ie completely torn.
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Answer:
10.13
Explanation:
take note that velocity is distance over time (
) so you do 456(distance)÷45(time)= 10.13
Answer:
x = 0.081 m.
Explanation:
a) To find how much does the atmospheric pressure cause the spring to compress we need to use the following equation:
(1)
<u>Where</u>:
F: is the force
k: is the spring constant = 3300 N/m
x: is the distance of compression =?
The force can be found as follows:
<u>Where</u>:
P: is the atmospheric pressure = 101325 Pa
A: is the area of the piston = πr²
r: is the radius = 0.029 m
Now, from equation (1) we can find x:
Therefore, the atmospheric pressure causes the spring to compress 0.081 m.
I hope it helps you!
Answer:
At the very bottom, whnere the sag is the greatest, Jay’s acceleration is upward.
Explanation:
As Jay lands on the trampoline, Jay’s motion was dowward, the trampoline was opposing his motion and hence, caused him to reach an initial halt position. Afterwards, the trampoline causes Jay to move back into the air and therefore, the change in velocity vector act in upward direction. The acceleration vector is always align towards the change in velocity vector's direction.
Answer:
Explanation:
Let the initial velocity of small block be v .
by applying conservation of momentum we can find velocity of common mass
25 v = 75 V , V is velocity of common mass after collision.
V = v / 3
For reaching the height we shall apply conservation of mechanical energy
1/2 m v² = mgh
1/2 x 75 x V² = 75 x g x 10
V² = 2g x 10
v² / 9 = 2 x 9.8 x 10
v² = 9 x 2 x 9.8 x 10
v = 42 m /s
small block must have velocity of 42 m /s .
Impulse by small block on large block
= change in momentum of large block
= 75 x V
= 75 x 42 / 3
= 1050 Ns.
