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astraxan [27]
3 years ago
6

A standard drink of beer is _ ounces.

Chemistry
2 answers:
kiruha [24]3 years ago
4 0

A standard drink of beer is 12 ounces


ollegr [7]3 years ago
3 0
A standard drink of beer is 12 ounces.
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Two hundred grams of a substance requires 9.76kj of heat to raise its temperature from 25 C to 45 C. It has a specific heat of 2
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Two separate masses of zinc were measured on a laboratory balance. The first zinc had a sample mass of 210.10g, and the second z
wlad13 [49]

Answer:

Density is  7.15 g /mL.

Mass is  445.2 g.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of first zinc sample = 210.10 g

Mass of second zinc sample = 235.10 g

Combined volume = 62.3 mL

Density of combined sample ?

Mass of combined sample = ?

Solution:

Mass of combined sample = 210.10 g + 235.10 g = 445.2 g

density = mass / volume

density = 445.2 g / 62.3 mL

density = 7.15 g /mL

3 0
3 years ago
A 400. 0 g sample of liquid water is at 30. 0 ºc. how many joules of energy are required to raise the temperature of the water t
Agata [3.3K]

Energy required to raise the temperature from 35°C - 45 °C= 25116 J.

specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.

solving,

Sample of liquid = 400. 0 g

temperature = 30. 0 ºc

joules of energy are required to raise the temperature of the water to 45. 0 ºc

therefore rise in temperature 45 - 30 = 15°C

Specific heat capacity = 4.186 J/g m °C

In kelvin = 273 + 15 = 288

          = ∴ energy required = Q = m s ( t final - t initial)

            =  400*4.186 * 15

           = 25116 joule

Learn more about specific heat here:-brainly.com/question/21406849

#SPJ4

7 0
1 year ago
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