Answer:
<h2>7.65 litres </h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is

Since we're finding the new volume

15 kPa = 15,000 Pa
50 kPa = 50,000 Pa
We have

We have the final answer as
<h3>7.65 litres </h3>
Hope this helps you
Answer:
D
Explanation:
When a conclusions is shared it gives room for other scientist with other ideas or different perspective to raise up new questions
Are u talking about electron sublevel config or where the electrons show in the "rings" of the atom
Answer : The excess reactant in the combustion of methane in opem atmosphere is
molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,

First we have to calculate the moles of methane.
=
= 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give
moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is
molecule.