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zaharov [31]
3 years ago
14

Globalization concerns many workers because ________.

Physics
2 answers:
never [62]3 years ago
7 0

Answer:

Companies will tend to seek lower costs by outsourcing labor

Explanation:

Globalization, in its current form, is led by the large multinationals and neoliberalism. Thus, large corporations settle in many underdeveloped countries in search of abundant raw material and cheap labor. This cheap labor has no alternative but to be subjected to low wages, which, in general terms, ends up shaping the source of misery worldwide. This has been worrying many workers, as the cheapness of mother labor results in lower quality of life for them and their families.

Cloud [144]3 years ago
6 0
Globalization concerns many workers because companies will tend to seek lower costs by outsourcing labor.
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Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ball
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This is an example of an elastic collision. The two objects collide and return to their original shapes and move separately. In such a collision, kinetic energy is conserved. I think we can agree that this represents Newton's third law by demonstrating conservation of momentum.
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3 years ago
Read 2 more answers
A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m
Eduardwww [97]

Answer:

The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

Explanation:

Given;

weight of the man, W = 700 N

Weight of the woman, W = 440 N

momentum is given by;

P = mv\\\\v = \frac{P}{m}

Kinetic energy of the man;

K_m = \frac{1}{2}m_m(\frac{P_m}{m_m})^2  \\\\K_m = \frac{P_m^2}{2m_m}

Momentum of the man is calculated as;

P_m^2 = 2m_mK_m

The kinetic energy of the woman is given by;

K_w = \frac{P_w^2}{2m_w}

The momentum of the woman is given;

P_w^2 = 2m_wK_w

Since, momentum of the man = momentum of the woman

P_m^2 = P_w^2

2m_mK_m = 2m_wK_w\\\\\frac{K_m}{K_w} = \frac{2m_w}{2m_m}\\\\\frac{K_m}{K_w} = \frac{m_w}{m_m}

mass of the mas = 700 / 9.8 = 71.429

mass of the woman is = 440 / 9.8 = 44.898

\frac{K_m}{K_w} = \frac{44.898}{71.429}\\\\\frac{K_m}{K_w} =0.629

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

3 0
3 years ago
Describe a scenario where a car's speed could stay the same, but the acceleration changes.
k0ka [10]

Answer:

An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes.

Explanation:

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3 years ago
One way to search for planets around other stars is the doppler technique. another way uses transits of planets around other sta
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The transit method requires watching the light output of a star over long periods of time. A transit occurs when the planet crosses in front of its star from earths point of view. Since there is a small object (the planet) now blocking some of the star, it appears to dim a little bit for a while until the planet passes. If we are in a position where that occurs regularly (most paths of planets do not happen to be on the line of sight between earth and their star) we can deduce the period of orbit. From the amount of dimming and the period you can estimate the mass
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A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k
Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

I_1=m_1r^2

I_1=7\times (0.25)^2=0.437\ kgm^2

The moment of inertia of the rod about one end is given by :

I_2=\dfrac{m_2l^2}{3}

l = r

I_2=\dfrac{m_2r^2}{3}

I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2

For 6 spokes, I_2=0.025\times 6=0.15\ kgm^2

So, the net moment of inertia of the wagon is :

I=I_1+I_2

I=0.437+0.15=0.587\ kgm^2

So, the moment of inertia of the wagon wheel for rotation about its axis is 0.587\ kgm^2. Hence, this is the required solution.

4 0
3 years ago
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