Answer:
(a) 2.624
(b) 1.334
Explanation:
The given data in the question is:
Mass = 2.95 kg
Spring constant "k" = 820 N/m
Compression of Spring "x" = 0.0800m
Using this data and the equation to find the answer for spring potential energy:
spring potential energy = 1/2 kx²
= 1/2 (820 N/m)(0.0800m)²
= 2.624 Joules
(b) - It is given that the surface is friction-less which means no loss of energy during the motion of spring. This means that all the potential energy possessed by the spring converts to Kinetic Energy of the block. We can equate spring potential energy with Kinetic energy to find the block's speed as below:
Kinetic Energy = 1/2mv² where "m" is mass and "v" is velocity of the object
1/2mv² = spring potential energy (found in part "a" above)
1/2(2.95 kg)v² = 2.624 Joules
v² = (2.624 x 2) / 2.95
v² = 1.779
v = √1.779
v = 1.334 m/s
Answer:
Animal-like protists are those which cannot make their own food. These protists have the ability to move themselves and are often further subdivided into groups based on how they move. Plant-like protists are those that make their own food using sunlight and water. They can live in water or on trees.
Explanation:
Answer: 50 km, 0, 27.78 m/s
Explanation:
Given
Circumference of the track is ![12.5\ km](https://tex.z-dn.net/?f=12.5%5C%20km)
Speed of car is ![100\ km/h](https://tex.z-dn.net/?f=100%5C%20km%2Fh)
Car drives for ![30\ \text{minute}\ or\ 0.5\ hr](https://tex.z-dn.net/?f=30%5C%20%5Ctext%7Bminute%7D%5C%20or%5C%200.5%5C%20hr)
(a)Distance traveled is
![\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km](https://tex.z-dn.net/?f=%5CRightarrow%20D%3D100%5Ctimes%200.5%5C%5C%5CRightarrow%20D%3D50%5C%20km)
(b)displacement of the car
It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.
Therefore, the displacement of the car is zero.
(c)To convert kmph to m/s, multiply the entity by ![\frac{5}{18}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B18%7D)
![\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s](https://tex.z-dn.net/?f=%5CRightarrow%20100%5Ctimes%20%5Cdfrac%7B5%7D%7B18%7D%5C%5C%5C%5C%5CRightarrow%2027.78%5C%20m%2Fs)
Answer:
230.4 N
Explanation:
Applying,
F = kqq'/r²..................... Equation 1
Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.
From the question,
Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m
Constant: k = 9×10⁹ Nm²/C²
Substitute these values into equation 1
F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²
F = (576×10⁻³)/0.0025
F = 230.4 N.