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3 years ago

7

Which of these is one of six most common elements found in the human body??

1 answer:

Lady bird [3.3K]3 years ago

6 0

Answer: Oxygen

Explanation: Oxygen is the most common element in the human body. It makes up 65% of the body.

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How do I solve for this?

vova2212 [387]

I can’t see anything

7 0

2 years ago

A vector has an x-component

NeTakaya

Answer:

34.45m

Explanation:

Magnitude of a vector is equal to the square root of sum of squares of x & y vectors.

Magnitude = $\sqrt({x^2} + {y^2})$

= $\sqrt({19.5^2} + {28.4^2})$

=34.45m

5 0

3 years ago

ΔP = 1.88 x 10^4 Pa. Use this answer to estimate the volume flow rate of blood from the head to the feet of a six-foot-tall pers

Sveta_85 [38]

Answer: $3765.66 \frac{m^{3}}{s}$

Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

$Q=\frac{\pi r^{4}\Delta P}{8\eta L}$

Where:

$Q$ is the Volume flow rate

$r=23 cm \frac{1 m}{100 cm}=0.23 m$ is the effective radius

$L=6 ft \frac{0.3048 m}{1 ft}=1.8288 m$ is the length

$\Delta P=1.88(10)^{4} Pa$ is the difference in pressure

$\eta=3(10)^{-3} Pa.s$ is the viscosity of blood

Solving:

$Q=\frac{\pi (0.23 m)^{4}(1.88(10)^{4} Pa)}{8(3(10)^{-3} Pa.s)(1.8288 m)}$

$Q=3765.66 \frac{m^{3}}{s}$

7 0

3 years ago

Which of the following quantities is a scalar?

djyliett [7]

Answer:

Option C

Explanation:

Scalar quantities are described by its magnitude only. They do not need to be described by the direction. So, 20 miles per hour is the scalar quantity.

6 0

3 years ago

Read 2 more answers

Early in the morning, when the temperature is 4.5 ∘C, gasoline is pumped into a car's 53-L steel gas tank until it is filled to

Lynna [10]

Answer:

$\Delta V=1.0911\ L$

Explanation:

Given:

Initial temperature, $T_i=4.5^{\circ}C$

initial volume, $V_i=53\ L$

final temperature, $T_f=27^{\circ}C$

volumetric coefficient of thermal expansion for gasoline, $\beta_g=950\times 10^{-6}\ K^{-1}$

volumetric coefficient of thermal expansion for steel, $\beta_s=35\times 10^{-6}\ K^{-1}$

<u>Now the increment in the volume of the container:</u>

$\Delta V_s=V_i.\beta_s.\Delta T$

$\Delta V_s=53\times 35\times 10^{-6}\times (27-4.5)$

$\Delta V_s=41737.5\times 10^{-6}\ L$

<u>and the increment in the volume of the gasoline:</u>

$\Delta V_g=V_i.\beta_g.\Delta T$

$\Delta V_g=53\times 950\times 10^{-6}\times (27-4.5)$

$\Delta V_g=1132875\times 10^{-6}\ L$

<u>Hence the difference in the increment of the two volumes:</u>

$\Delta V=\Delta V_g-\Delta V_s$

$\Delta V=(1132875-41737.5)\times 10^{-6}$

$\Delta V=1.0911\ L$ of the gasoline spills out of the container in this case.

3 0

3 years ago