Answer:
g = 4.7 ×
m/
Explanation:
Given that the mass of the satellite = 700 kg, and 10,000 m above the earth;s surface.
From Newton's second law,
F = mg ............... 1
From Newton's gravitation law,
F =
.................. 2
Where: F is the force, G is the gravitational constant, M is the mass of the first body, m is the mass of the second body, g is the gravitational force and r is the distance between the centers of the two bodies.
Equate 1 and 2 to have,
mg = 
⇒ g = 
But; G = 6.67 ×
N
, M = 700 Kg, r = 10000 m
Thus,
g = 
= 
= 4.669 ×
m/
The force of gravity on the satellite is 4.7 ×
m/
.
Unit for x - the change in the spring length:
x = [ m ]
PE s = 1/2 k x²
[ kg m² / s² ] = 1/2 k * [ m² ] /: m²
k = [ kg / s² ]
Answer: The unit for spring constant k is kg/ s²
Answer:
Bok.............................