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Setler [38]
3 years ago
12

A constant force is exerted for a short distance on a block of mass that is initially at rest on a horizontal frictionless plane

. This force gives the block a certain final speed v. Suppose we repeat the experiment but, instead of starting from rest, the block is already moving with constant speed 2 v in the direction of the force at the moment we begin to apply the force. After we exert the same constant force for the same distance, the increase in the block’s speed 1.( √5+2)v
2. 0

3. v

4. cannot be determined from the informa- tion provided.

5. (√5 − 2) v

6. (√3 − 2) v

7. (√2 − 1) v

8. (√3 − 1) v
Physics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

v

Explanation:

initial speed is 2v

final speed is 3v

increase is v

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A car driving down a hill contains many types of energy. DESCRIBE at least 3 types of energy the car has.
VikaD [51]

Once the car is on top of the hill it contains potential energy witch means it is storing enough energy to slide the hill until acted on. Once the car moves and slides down the hill it creates kinetic energy witch means it's in motion. The car then turns the kinetic energy into mechanical energy witch means it's working. I'm not sure if that helped but good luck!

8 0
3 years ago
In a police ballistics test, a 10.0-g bullet moving at 300 m/s is fired into a 1.00-kg block at rest. The bullet goes through th
natta225 [31]

Answer:

Speed of block after the bullet emerges = 1.5 m/s

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum.

Mass of bullet = 10 g = 0.01 kg

Initial Velocity of bullet = 300 m/s

Mass of block = 1 kg

Initial Velocity of block = 0 m/s

Final Velocity of bullet = 50% of initial velocity. = 150 m/s

We need to find final velocity of block. Let it be v

We have

Initial momentum = 0.01 x 300 + 1 x 0 = 3 kg m/s

Final momentum = 0.01 x 150 + 1 x v = 1.5 + v

Equating

3 = 1.5 + v

v = 1.5 m/s

Speed of block after the bullet emerges = 1.5 m/s

3 0
3 years ago
A series R-L-C circuit is connected to a 70.0 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 80.0 Ω and a
Andreyy89

Answer:

62.7 VA

Explanation:

The apparent power (power supplied by the source) of an AC circuit is determined by

S = \frac{(Vrms)^2}{Z}

The impedance(Z) depends on the frequency, but in this case it is given to us that it is 102 ohms at this frequency.

So:

S = \frac{(80 V)^2}{102 \Omega} = 62.7 VA

3 0
3 years ago
An object moves at 60 m/s in the +x direction. As it passes through the origin it gets a 4.5 m/s^2 acceleration in the -x direct
Brut [27]

Answer:

a) After 26.67 seconds it returns back to the origin

b) Velocity when it returns to the origin = 60 m/s in the -x direction

Explanation:

a) Let the starting position be origin and time be t.

  After time t displacement, s = 0 m

  Initial velocity, u = 60 m/s

  Acceleration, a = -4.5 m/s²

 We have equation of motion s = ut + 0.5 at²

 Substituting

        s = ut + 0.5 at²

        0 = 60 x t + 0.5 x (-4.5) x t²        

        2.25t² - 60 t = 0

        t² - 26.67 t = 0

        t (t-26.67) = 0

      t = 0s or t = 26.67 s

So after 26.67 seconds it returns back to the origin

b) We have equation of motion v = u + at

  Initial velocity, u = 60 m/s

  Acceleration, a = -4.5 m/s²

  Time , t = 26.67

 Substituting

        v = 60 - 4.5 x 26.67 = -60 m/s

Velocity when it returns to the origin = 60 m/s in the -x direction

 

4 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST IF RIGHT!!!!
marta [7]

Answer:

The answer is D

Hope this helped

PLEASE GIVE BRAINLIEST

Explanation:

6 0
3 years ago
Read 2 more answers
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