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Setler [38]
2 years ago
12

A constant force is exerted for a short distance on a block of mass that is initially at rest on a horizontal frictionless plane

. This force gives the block a certain final speed v. Suppose we repeat the experiment but, instead of starting from rest, the block is already moving with constant speed 2 v in the direction of the force at the moment we begin to apply the force. After we exert the same constant force for the same distance, the increase in the block’s speed 1.( √5+2)v
2. 0

3. v

4. cannot be determined from the informa- tion provided.

5. (√5 − 2) v

6. (√3 − 2) v

7. (√2 − 1) v

8. (√3 − 1) v
Physics
1 answer:
Irina-Kira [14]2 years ago
7 0

Answer:

v

Explanation:

initial speed is 2v

final speed is 3v

increase is v

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To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

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c = Propagation speed of waves in the medium

v_r= Speed of the receiver relative to the medium

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The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

v_s = 32.2m/s \rightarrow Velocity of car

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Replacing we have that

f = \frac{c + v_r}{c - v_s}f_0

f = \frac{343 + 14.8}{343 - 32}(523)

f = 601.7Hz

Therefore the frequency that hear the motorcyclist is 601.7Hz

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An airplane travels 4000m in 16 seconds on a heading of 35 whats is its velocity
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In the question, you just gave a complete and detailed
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A modern compact fluorescent lamp contains 1.4 mg of mercury (Hg). If each mercury atom in the lamp were to emit a single photon
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Answer:

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n=\frac{m}{M_m}

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Substituting, we find

n=\frac{0.0014 g}{200.6 g/mol}=7.0\cdot 10^{-6} mol

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4 0
3 years ago
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