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tangare [24]
2 years ago
14

Una barra conductora de L = 0,9 m se mueve sin fricción sobre dos rieles conductores horizontales, Unos extremos de los rieles s

e conectan a una batería de 15 V y un interruptor.
La barra se mueve en una región donde existe un campo magnético uniforme
B = −1,5 ˆz T. La barra tiene una masa de 0,5 kg y una resistencia de 8 Ω.
a) Encuentre la aceleración de la barra, en t = 0 s, justo cuando se cierra el interruptor.
b) Encuentre la aceleración de la barra cuando se mueve hacia la derecha con rapidez 2 m/s.
Physics
1 answer:
MAVERICK [17]2 years ago
8 0

Answer:

sorry I don't understand

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Particles in which state are close together, yet free to move around one another?
enyata [817]
Particles in the liquid state of matter are close together, yet free to move around one another
4 0
3 years ago
The space shuttle releases a satellite into a circular orbit 630 km above the Earth.
solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

  • \displaystyle g=\frac{GM}{r^2}

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

  • \displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}

Remove units to make the equation easier to read.

  • \displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}

Multiply the numerator out.

  • \displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}

Add the terms in the denominator.

  • \displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}

Simplify this equation.

  • \displaystyle g=8.11045189 \ \frac{m}{s^2}

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

  • \displaystyle a = \frac{v^2}{r}

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.

  • \displaystyle 8.11045189 \ \frac{m}{s^2}  = \frac{v^2}{7008100 \ m}  

Remove units to make the equation easier to read.

  • \displaystyle 8.11045189   = \frac{v^2}{7008100}

Multiply both sides by 7,008,100.

  • 56838857.89=v^2

Take the square root of both sides.

  • v=7539.154985

The shuttle should be moving at a velocity of about 7,539 m/s when it is released into the circular orbit above Earth.

5 0
2 years ago
In the visible spectra of stars, absorption lines of hydrogen are produced when atoms are excited from n = 2 to higher levels (t
grigory [225]

Answer:

3. relatively high temperature, about 10,000 K, so that significant numbers of electrons are excited from the ground state, n = 1, to the first excited state, n = 2, but not too many of them have been ejected completely from the atoms

Explanation:

If hydrogen absorption lines are very strong in the visible spectrum of a particular star that means the population of electron in n = 2 is very high so on being exited they absorb radiation in Balmer series and give rise to absorption spectrum. The average temperature required to excite electron in hydrogen atom from n=1 to n = 2   is 10000K .

4 0
3 years ago
When a bow is stretched back and an arrow is shot, what type of energy conversion has occurred?
Lelechka [254]
D. mechanical to elastic
6 0
3 years ago
A person walks 24 meters at 3 m/s. How long did it take them
asambeis [7]

Hi my dear friend,

2m*30 = 60m

~Thank you

4 0
3 years ago
Read 2 more answers
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