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tangare [24]
2 years ago
14

Una barra conductora de L = 0,9 m se mueve sin fricción sobre dos rieles conductores horizontales, Unos extremos de los rieles s

e conectan a una batería de 15 V y un interruptor.
La barra se mueve en una región donde existe un campo magnético uniforme
B = −1,5 ˆz T. La barra tiene una masa de 0,5 kg y una resistencia de 8 Ω.
a) Encuentre la aceleración de la barra, en t = 0 s, justo cuando se cierra el interruptor.
b) Encuentre la aceleración de la barra cuando se mueve hacia la derecha con rapidez 2 m/s.
Physics
1 answer:
MAVERICK [17]2 years ago
8 0

Answer:

sorry I don't understand

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How is the independent variable affected by the dependent variable
stiv31 [10]

Answer:

A dependent variable is a variable that is tested in an experiment. An independent variable is that can be modified. Depending on what you are testing, the dependent variable will change accordingly to the dependent variable.

- I'm reading this back and it doesn't make much sense, if you want me to reword this I can

5 0
2 years ago
The tension in the horizontal towrope pulling a water-skier is 250 N while the skier moves due west a distance of 50 m. How much
icang [17]

Answer:

W = 250(50) = 12500 J

Explanation:

5 0
3 years ago
What is the mechanical advantage of a wedge that is 2 inches at its widest part and has a sloped side with a length of 10 inches
Delicious77 [7]
The correct answer would be 5 hope this helps.
7 0
3 years ago
Read 2 more answers
A positively charged object is brought near but not in contact with the top of an uncharged gold leaf electroscope. The experime
Olin [163]

Answer:

The leaves of the electroscope move further apart.

Explanation:

This is what happens; when the positive object is brought near the top, negative charges migrating from the gold leaves to the top. This is because the negative charges in the gold are attracted by the positive charge. Thus, it leaves behind a net positive charge on the leaves, though the scope remains neutral overall. To that effect, the leaves repel each other and move apart. If a finger touches the top of the electroscope at the moment when the positive object remains near the top, it basically grounds the electroscope and thus the net positive charge in the leaves flows to the ground through the finger. However, the positive object continues to "hold" negative charges in place at the top. Ar this moment the gold leaves have lost their net positive charge, so they no longer repel, and they move closer together. If the positive object is moved away, the negative charges at the top are no longer attracted to the top, and they redistribute themselves throughout the electroscope, moving into the leaves and charging them negatively.

Thus, the leaves move apart from each other again and we now have a negatively charged electroscope. If a negatively charged object is now brought close to the top, but without touching, the negative charges already in the electroscope will be repelled down toward the leaves, thereby making them more negative, causing them to repel more, and hence move even further apart.

So, the leaves move further apart.

7 0
2 years ago
If the 250 kg bumper car that you are riding in hits another bumper car that is sitting still while driving 3.5 m/s, how much fo
Vilka [71]

Answer:

875 N

Explanation:

From this question, you didn't state the time taken for the bumper car to move or to hit the other bumper car. In calculations of force, time is often needed, because

Force = mass * acceleration, while

Acceleration = velocity / time, basically

Force = mass * velocity / time.

We have our mass, we have our velocity, but we haven't time. So, for this calculation, I'd assume our time to be 1s.

Going by the formula I stated, we can then say that

Force = 250 * 3.5 / 1

Force = 875 N

This means the force my bumper car have while moving at 3.5 m/s for an estimated time of 1s is 875 N

3 0
2 years ago
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