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mars1129 [50]
3 years ago
14

Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿Cuál es la lon

gitud del camino recorrido al cabo de 3.0 segundos? Porfa es para mañana
Physics
2 answers:
In-s [12.5K]3 years ago
6 0

Answer:

The equation that we have is:

X = 10m + 20m/s*t -4.9m/s^2*t^2

where x is the position of an object in meters and t is in seconds.

Now, we want to know the distance that the object moves in 3 seconds.

This can be calculated as:

X(3) - X(0) = 10m + 20m/s*3 -4.9m/s^2*3^2 - 10m = 15.9m

So the object moves 15.9 metes in the first 3 seconds.

now in Spanish.

La ecuación que tenemos es:

X = 10m + 20m / s * t -4.9m / s ^ 2 * t ^ 2

donde x es la posición de un objeto en metros yt está en segundos.

Ahora, queremos saber la distancia que se mueve el objeto en 3 segundos.

Esto se puede calcular como:

X (3) - X (0) = 10m + 20m / s * 3 -4.9m / s ^ 2 * 3 ^ 2 - 10m = 15.9m

Entonces el objeto se mueve 15.9 metes en los primeros 3 segundos.

lora16 [44]3 years ago
4 0

Answer:

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

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3 years ago
Vector B has x, y, and z components of 2.4,
Fed [463]

The magnitude of the vector B is 10.9

A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.

To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.

Vector B has components,

x = 2.4

y = 9.8

z = 4.1

Applying the formula,

|B| = √x²+y²+z²

|B| = √(2.4)² + (9.8)² + (4.1)²

|B| = √5.76+96.04+16.81

|B| = √118.61

|B| = 10.9

Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)

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