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mars1129 [50]
3 years ago
14

Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿Cuál es la lon

gitud del camino recorrido al cabo de 3.0 segundos? Porfa es para mañana
Physics
2 answers:
In-s [12.5K]3 years ago
6 0

Answer:

The equation that we have is:

X = 10m + 20m/s*t -4.9m/s^2*t^2

where x is the position of an object in meters and t is in seconds.

Now, we want to know the distance that the object moves in 3 seconds.

This can be calculated as:

X(3) - X(0) = 10m + 20m/s*3 -4.9m/s^2*3^2 - 10m = 15.9m

So the object moves 15.9 metes in the first 3 seconds.

now in Spanish.

La ecuación que tenemos es:

X = 10m + 20m / s * t -4.9m / s ^ 2 * t ^ 2

donde x es la posición de un objeto en metros yt está en segundos.

Ahora, queremos saber la distancia que se mueve el objeto en 3 segundos.

Esto se puede calcular como:

X (3) - X (0) = 10m + 20m / s * 3 -4.9m / s ^ 2 * 3 ^ 2 - 10m = 15.9m

Entonces el objeto se mueve 15.9 metes en los primeros 3 segundos.

lora16 [44]3 years ago
4 0

Answer:

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

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