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mars1129 [50]
3 years ago
14

Un cuerpo se mueve en línea recta segun la ecuación x=10+20t-4.9t2 (x está expresado en metros y t en segundos). ¿Cuál es la lon

gitud del camino recorrido al cabo de 3.0 segundos? Porfa es para mañana
Physics
2 answers:
In-s [12.5K]3 years ago
6 0

Answer:

The equation that we have is:

X = 10m + 20m/s*t -4.9m/s^2*t^2

where x is the position of an object in meters and t is in seconds.

Now, we want to know the distance that the object moves in 3 seconds.

This can be calculated as:

X(3) - X(0) = 10m + 20m/s*3 -4.9m/s^2*3^2 - 10m = 15.9m

So the object moves 15.9 metes in the first 3 seconds.

now in Spanish.

La ecuación que tenemos es:

X = 10m + 20m / s * t -4.9m / s ^ 2 * t ^ 2

donde x es la posición de un objeto en metros yt está en segundos.

Ahora, queremos saber la distancia que se mueve el objeto en 3 segundos.

Esto se puede calcular como:

X (3) - X (0) = 10m + 20m / s * 3 -4.9m / s ^ 2 * 3 ^ 2 - 10m = 15.9m

Entonces el objeto se mueve 15.9 metes en los primeros 3 segundos.

lora16 [44]3 years ago
4 0

Answer:

La longitud del camino recorrido es de 25.9 [m]

Explanation:

Se reemplaza el valor de tiempo en segundos en la ecuación dada de desplazamiento

x=10+20*(3) - 4.9*(3)^2

x= 25.9 [metros]

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A plane has a takeoff speed of 89.3m/s and requires 1465m to reach that speed determine the acceleration of the plane and the ti
Tems11 [23]

Answer:

a = 2.72 ms⁻²

32.83 s

Explanation:

By using the kinematic equations you get,

v² = u² +2as and v = u + at   where all terms in usual meaning

Using 1st equation,

89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²

By 2nd equation,

89.3 = 0 + 2.72×t ⇒ t = 32.83 s

4 0
3 years ago
Suppose a tank filled with water has a liquid column with a height of 19 meter. If the area is 2 square meters 2m squared, what’
ycow [4]

Answer:

  372,400 N

Explanation:

The volume of the column is ...

  V = Bh = (2 m^2)(19 m) = 38 m^3

If we assume the density is 1000 kg/m^3, then the mass of the water is ...

  M = ρV = (1000 kg/m^3)(38 m^3) = 38,000 kg

The force of gravity on that mass is ...

  F = Mg = (38,000 kg)(9.8 m/s^2) = 372,400 N

4 0
3 years ago
What electric force would a stationary 3.8 C charge experience if it were far away from any other charges
MAVERICK [17]

Answer:

The electric force will be  0 N

Explanation:

From the question we are told that

   The magnitude of the charge is  q_1 = 3.8 \ C

   

Generally from Coulombs law the electric force  between two charges is mathematically represented as

         F = \frac{ k  *  q_1 q_2 }{r^2}

Here r is the distance of separation between that two charges.

  Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is  r = \infty

So

       F = \frac{ k  *  3.8  * q_2 }{\infty^2}

=>    F =0 \ N

Hence the electric force will be  0 N

3 0
2 years ago
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in
algol [13]

Answer: Magnitude of the force exerted on the egg by the ground is 9.2N

Explanation:

Given the following :

Mass of egg (m) = 150g = 0.15kg

Height(h) from which egg is dropped = 3m

velocity of egg before hitting the ground (u) = 4.4m/s

Final velocity of egg (V) = 0

Time taken (t) = 0.072s

Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:

Momentum = mass × velocity

From Newton's second law:

Force = mass × change in Velocity with time ;

That is

F = m * ΔV / t

Inputting our values

F = 0.15 * (4.4 - 0) / 0.072

F = 0.15 × (4.4 / 0.072)

F = 0.15 × 61.11

F = 9.16N

F = 9.2N

8 0
2 years ago
An capacitor consists of two large parallel plates of area A separated by a very small distance d. This capacitor is connected t
scoundrel [369]

Answer:

Will be doubled.

Explanation:

For a capacitor of parallel plates of area A, separated by a distance d, such that the charges in the plates are Q and -Q, the capacitance is written as:

C = \frac{Q}{V}  = e_0\frac{A}{d}

where e₀ is a constant, the electric permittivity.

Now we can isolate V, the potential difference between the plates as:

V = \frac{Q}{e_0} *\frac{d}{A}

Now, notice that the separation between the plates is in the numerator.

Thus, if we double the distance we will get a new potential difference V', such that:

V' = \frac{Q}{e_0} *\frac{2d}{A} = 2*( \frac{Q}{e_0} *\frac{d}{A}) = 2*V\\V' = 2*V

So, if we double the distance between the plates, the potential difference will also be doubled.

6 0
2 years ago
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