Calculate the longest wavelength visible to the human eye 164 kj mol

1 answer:

const2013 [10]4 years ago

8 0

The working equation to be used here is the Planck's equation. This was derived using the wave behavior theory of the light and electromagnetic waves. According to this equation, electron transfer from orbital to orbital in discrete packets of energy called quanta. When an electron moves to a higher energy level, it absorbs energy. On the other hand, when it lowers to an energy level, it releases energy by emitting light. Hence, the wavelength of the light or magnetic wave can be determined.

E = hν = hc/λ, where ν is the frequency, λ is the wavelength, h is the Planck's constant equal to 6.626×10⁻³⁴ J-s and c is the speed of light equal to 3×10⁸ m/s.

Knowing the energy to be 164 kJ or 164,000 J, the wavelength is equal to

164,000 = (6.626×10⁻³⁴)(3×10⁸ m/s)/λ
λ = 1.212×10⁻³⁰ meters

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Proton: Its electrical charge is +1, its mass is 1, it's found in the nucleus

Neutron: Its electrical charge is 0, its mass is 1, it's found in the nucleus

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Explanation:

Atoms consist of three types of particles:

Proton: the proton is found in the nucleus of the atom, and it has a positive electric charge, equal to $+1.6\cdot 10^{-19}C$ (expressed in units of fundamental charge, it has a charge of +1). Its mass is $1.67\cdot 10^{-27}kg$ , while its mass expressed in atomic mass units is 1 a.m.u
Neutron: the neutron is also found in the nucleus of the atom, and it has no electric charge. Its mass is similar to the mass of the proton (slightly larger), and neutrons and protons are held together in the nucleus by the presence of the strong nuclear force
Electron: the electron orbits around the nucleus, far away from it. It has negative electric charge, opposite to that of the proton ( $-1.6\cdot 10^{-19}C$ , or -1 in units of fundamental charge). Its mass is much lower than that of the proton, approximately 1800 times smaller, so it can be considered as negligible.