Answer:
(a) T = 0.412s
(b) f = 2.42Hz
(c) w = 15.25 rad/s
(d) k = 86.75N/m
(e) vmax = 5.03 m/s
Explanation:
Given information:
m: mass of the block = 0.373kg
A: amplitude of oscillation = 22cm = 0.22m
T: period of oscillation = 0.412s
(a) The period is the time of one complete oscillation = 0.412s
The period is 0.412s
(b) The frequency is calculated by using the following formula:

The frequency is 2.42 Hz
(c) The angular frequency is:

The angular frequency is 15.25 rad/s
(d) The spring constant is calculated by solving the following equation for k:

The spring constant is 86.75N/m
(e) The maximum speed is:

(f) The maximum force applied by the spring if for the maximum elongation, that is, the amplitude:

The maximum force that the spring exerts on the block is 17.35N
Answer:
10,600 m
Explanation:
Use range equation:
R = v₀² sin(2θ) / g
R = (433.0 m/s)² sin(2 × 64.8°) / (9.8 m/s²)
R = 14,700 m
The range is shortened by 28.1%.
0.719R = 10,600 m
The amount of gravitational pull an object experiences is its mass
<h3>
What is Weight ?</h3>
Weight can be define as gravitational pull an object. It is a product of mass and acceleration due to gravity. That is, W = mg. It is measured in Newton (N)
The amount of gravitational pull an object experiences is its mass and not density because the weight of an object depend on its mass and acceleration due to gravity.
W = mg
where
- g = acceleration due to gravity
Therefore, the amount of gravitational pull an object experiences is its mass
Learn more about Weight here: brainly.com/question/19753744
#SPJ1
Explanation:
1. The kinetic energy of any object is calculated as :
...........(1)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of velocity, ![[v]=[LT^{-1}]](https://tex.z-dn.net/?f=%5Bv%5D%3D%5BLT%5E%7B-1%7D%5D)
![[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5Cdfrac%7B1%7D%7B2%7D%5BM%5D%28%5BLT%5E%7B-1%7D%5D%29%5E2)
So, ![[ML^2T^{-2}]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
LHS = RHS
2. The potential energy is given by :

Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of g is ![[LT^{-2}]](https://tex.z-dn.net/?f=%5BLT%5E%7B-2%7D%5D)
Dimensional formula of height is ![[L]](https://tex.z-dn.net/?f=%5BL%5D)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
So, ![E=[M][LT^{-2}][L]](https://tex.z-dn.net/?f=E%3D%5BM%5D%5BLT%5E%7B-2%7D%5D%5BL%5D)
So, LHS = RHS
Hence, this is the required solution.