1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Minchanka [31]
3 years ago
8

An atom of an element forms a 2+ ion. In which group on the Periodic Table could this element be located?

Chemistry
1 answer:
Mashutka [201]3 years ago
3 0
To form a 2+ ion, you need to lose two negatively charged electrons. Because metals have relatively empty outer shells, they lose electrons. Metals are on the left hand side of the table, and in order to lose two electrons, you need to have two electrons to start with. The groups of the table are based on the number of electrons an element has in the outer shell, so Group 2 metals will lose two electrons to gain a 2+ charge
You might be interested in
Drag each tile to the correct location on the image.
nikdorinn [45]

Answer:

[He]: 2s² 2p⁵.

[Ne]: 3s².

[Ar]: 4s² 3d¹⁰ 4p².

[Kr]: 5s² 4d¹⁰ 5p⁵.

[Xe]: 6s² 4f¹⁴ 5d¹⁰ 6p².

Explanation:

  • Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.

  • [He]:

He contains 2 electrons fill 1s (1s²).

So, [He] can be written before the electronic configuration of 2s² 2p⁵.

  • [Ne]:

Ne contains 10 electrons fill (1s² 2s² 2p⁶).

So, [Ne] can be written before the electronic configuration of 3s².

  • [Ar]:

Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).

So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².

  • [Kr]:

Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).

So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.

  • [Xe]:

Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).

So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².

3 0
4 years ago
Read 2 more answers
The amount of heat involved in the synthesis of 1 mole of a compound from its elements, with all substances in their standard st
Pachacha [2.7K]

Answer:

A

Explanation:

8 0
3 years ago
Read 2 more answers
How does a Camel prevent the loss of water from their body?​
Schach [20]

Camels lose less water through their urine and feces than many other mammals. Their kidneys concentrate water heavily, leading to salty urine. The intestines also reabsorb water from intestinal material as it is digested, so dry feces are produced.

7 0
3 years ago
What volume of a 2.5 M NaOH solution is required to make 1 liter of a 0.75 M NaOH
defon
V1M1 = V2M2 

<span>V1 × 2.5 = 1 × 0.75,
so     V1 = 0.75/2.5
              = 0.3 </span>
6 0
3 years ago
Which integration phase moves the recovered person to the continental united states
nydimaria [60]
Phase 3 is the integration phrase
7 0
3 years ago
Other questions:
  • Describe the oceans and explain how the water cycle affects the salinity of the ocean?
    6·1 answer
  • When is a roman numeral most likely needed in the name of an ionic compound?
    9·2 answers
  • What is the maximum number of electrons allowed in the third energy level​
    10·2 answers
  • The spiral shape of the Milky Way Galaxy CANNOT be seen from Earth because ____?
    15·2 answers
  • Bohr models notes <br> The number of periods shows you the number of _______
    14·1 answer
  • Jeffrey is making a model of tungsten for his chemistry class. He has foam balls for the protons, neutrons, and electrons. He ha
    7·1 answer
  • A 250-mg sample of carbon from wood underwent 15300 carbon-14 disintegrations in 36 hours. Estimate the time since the death of
    11·1 answer
  • HNO3 + Mg(OH)2 yield Mg(NO3)2 + H2O​
    11·1 answer
  • In the artice, "As Sticky as a Gecko...but Ten
    5·2 answers
  • Natural gas (CH4) has a molar mass of 16.0 g/mole. You started out the day with a tank containing 200.0 g of natural gas. At the
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!