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3 years ago

An atom of an element forms a 2+ ion. In which group on the Periodic Table could this element be located?

1 answer:

3 0

To form a 2+ ion, you need to lose two negatively charged electrons. Because metals have relatively empty outer shells, they lose electrons. Metals are on the left hand side of the table, and in order to lose two electrons, you need to have two electrons to start with. The groups of the table are based on the number of electrons an element has in the outer shell, so Group 2 metals will lose two electrons to gain a 2+ charge

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Differentiate between sandy soil, clayey soil and loamy soil on the basis of the growth of plants????

ra1l [238]

The mixture of rock particle sand humus is called the soil.
If soil contains greater proportion of big particles it is called sandy soil. If the proportion of fine particles is relatively higher, then it is called clayey soil. If the amount of large and fine particles is about the same, then the soil is called loamy.

8 0

2 years ago

But-1-ene can be prepared from butan-1-ol. which type of reaction takes place?

slega [8]

Answer:

Dehydration Reaction

Explanation:

Alcohols can be converted into Alkenes using catalytic amounts of acids as a catalysts.

The water molecule is removed hence, it is called as dehydration reaction.

The reaction is attached.

8 0

2 years ago

How many grams of water are produced if 3.2 moles of hydrogen reacts

kotykmax [81]

JEKFKSLSKFHJSKSIDCOIZSUS

6 0

3 years ago

A child has a toy balloon with a volume of 1.80 L. The temperature of the balloon when it was filled was 293 K at a pressure of

Mekhanik [1.2K]

Answer:

2.42L

Explanation:

Given parameters:

V₁ = 1.8L

T₁ = 293K

P₁ = 101.3kPa

P₂ = 67.6kPa

T₂ = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

All the units are in the appropriate form. We just substitute and solve for the unknown;

101.3 x 1.8 / 293 = 67.6 x V₂ / 263

V₂ = 2.42L

7 0

3 years ago

How many moles of aluminum metal are required to produce 4.04 L of hydrogen gas at 1.11 atm and 27 °C by reaction with HCl?

Strike441 [17]

Answer:

0.121 moles of aluminum metal are required to produce 4.04 L of hydrogen gas at 1.11 atm and 27 °C by reaction with HCl

Explanation:

This is the reaction:

2 Al(s) + 6 HCl(aq) → 2 AlCl₃ (aq) + 3 H₂(g)

To make 3 moles of H₂, we need 2 moles of Al.

By conditions given, we will find out how many moles of H₂ do we have.

Let's use the Ideal Gas Law

P. V = n . R . T

1.11 atm . 4.04L = n . 0.082 L.atm/mol.K . 300K

(1.11 atm . 4.04L) / (0.082 mol.K/L.atm . 300K) = n

0.182 mol = n

So the rule of three will be:

If 3 moles of H₂ came from 2 moles of Al

0.182 moles of H₂ will come from x

(0.182 .2) / 3 = 0.121 moles

4 0

3 years ago