The answer to this question would be: ammonia
Chemical decomposition is the breakdown of a compound into smaller compound or element. In this question, the Sodium(Na), Argon (Ar) and Sulfur(S) is elements, not compounds.
An element should not breakable since it was the simplest form.
Ammonia(NH3) is a compound so it should be able to be decomposed.
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.
where,
- i: van 't Hoff factor (1 for non-electrolytes)
- Kf: cryoscopic constant
- m: molality
The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:
The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.
Learn more: brainly.com/question/2292439
Explanation:
Stoichiometry measures these quantitative relationships, and is used to determine the amount of products and reactants that are produced or needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry.
Answer:
Molarity = 1.4 M
Explanation:
Given data:
Mass of LiCl = 15.25 g
Volume of solution = 250 mL (250/1000 = 0.25 L)
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will calculate the number of moles of LiCl.
Number of moles = mass/molar mass
Number of moles = 15.25 g/ 42.39 g/mol
Number of moles = 0.36 mol
Molarity:
Molarity = 0.36 mol / 0.25 L
Molarity = 1.4 M (M= mol/L)
C₂H₆ + O₂ ----> CO₂ + H₂O
In order for an equation to be balanced there must be the same number of each atom on both sides
On the left side currently we have 2 C, 6 H, and 2 O
On the right side currently we have 1 C, 2 H, and 3 O
2C₂H₆ + 7O₂ ----> 4CO₂ + 6H₂O
Start by putting a 2 in front of C₂H₆
2C₂H₆ + O₂ ----> CO₂ + H₂O
we now have 4 Carbons on the left, so we need 4 carbons on the CO₂
2C₂H₆ + O₂ ----> 4CO₂ + H₂O
We also now have 12 H on the Left so we need to add a 6 to H₂O
2C₂H₆ + O₂ ----> 4CO₂ + 6H₂O
Finally with Oxygen we have 14 on the right side so we need to add a 7 to O₂
2C₂H₆ + 7O₂ ----> 4CO₂ + 6H₂O
Hope this helped!
