The formula that can be used to obtain a convergent series is given by;
a/1 – r.
<h3>What is a series?</h3>
In mathematics, we define a series as sum of numbers which could be convergent or divergent. In a convergent series, the summation of the numbers approaches a given value.
The formula that can be used to obtain a convergent series is given by;
a/1 – r.
Learn more about a convergent series:brainly.com/question/15415793?
#SPJ11
Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2
Easier to write, easier to read, easier to understand, easier to compare
Answer:
The electric bill for June is Rs198000
Explanation:
Convert volt to watt, but in order to do so I need to know the amps and since it is not provided I converted if the amps was 1.
I multiple 50 with 10 then with 30 so I know how much watt the fan takes at June.
Since there are 2 light bulb I multiple 10 with 2 than with 8 than with 30.
15000 watts for the fan,
4800 watts for light bulb,
add them and then times it by 10.
Rs198000
A) See ray diagram in attachment (-6.0 cm)
By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:
where
q is the distance of the image from the lens
f = -10 cm is the focal length (negative for a diverging lens)
p = 15 cm is the distance of the object from the lens
Solving for q,
B) The image is upright
As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:
where 
are the size of the image and of the object, respectively.
Since q < 0 and p > o, we have that 
, which means that the image is upright.
C) The image is virtual
As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.
This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual
