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kipiarov [429]
3 years ago
5

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se

lect one of the options below as your answer:. A. 1.6 newtons. B. 16 newtons. C. 22.5 newtons. D. 225 newtons. E. 2250 newtons.
Physics
2 answers:
stiks02 [169]3 years ago
5 0
Weight = Mas * Gravity = 60kg * 3.75 m/s² = 225 Newtons.

Option D.
aev [14]3 years ago
3 0
We know that:
w=mg
w=60kg*3,75m/s²
w=225N (d)
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A thin plate 6 ft long and 3 ft wide is submerged and held stationary in a stream of water (T = 60°F) that has a velocity of 17
VashaNatasha [74]

A) In the case of the Boundary Thickness Layer we use the given formula,

\delta = \frac{4.91x}{\sqrt{Re}}

We know as well that,

Re = Número de Reynolds = \frac{U*x}{\upsilon}

Where,

U = velocity

\upsilon = kinematic viscosity

For water, kinematic viscosity, \upsilon = 1.21*10^{-5} ft^2 /s

So, 500,000 = \frac{ 17x}{(1.21*10^{-5})}

x = 0.355 ft

d = \frac{4.91*0.355}{\sqrt {500000}}

d = 0.002465 ft = 0.029in

B) For flat plate boundary layer. Given the Critical Reynolds Number.= 5*10^5 we know that is equal to Re above.

Thus, x = 0.355 ft

C. Wall shear stress,

\tau = \mu*\sqrt{ U^3 / (2*\nu*x) }

For water, dynamic viscosity, \nu = 2.344*10^-5 lbf-s/ft^2

\tau = 2.344*10^-5 \sqrt {17^3 / (2*1.21*10^{-5}*0.355)}

\tau = 0.5605 lbf/ft^2

4 0
3 years ago
Explain how a generator creates electricity.
vlada-n [284]

Generators don't actually create electricity. Instead, they convert mechanical or chemical energy into electrical energy. They do this by capturing the power of motion and turning it into electrical energy by forcing electrons from the external source through an electrical circuit. hope it helps man

5 0
3 years ago
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A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment
snow_lady [41]

Answer:

18 radians

Explanation:

The computation is shown below:

As we know that

Torque = Force × Moment arm

= 1N × 1M

= 1N-M

Torque = I\alpha

\alpha = \frac{torque}{I}\\\\= \frac{1}{100}\\\\= 0.01 rad/s^2

Now

\theta = w_ot + \frac{1}{2} \alpha t^2\\\\w_o = 0\\\\\theta = 0 \times 60 + \frac{1}{2} \times 0.01 \times 60^2\\\\= 18\ radians

Here t = 1 minutes = 60 seconds

3 0
3 years ago
Does the mass of a pendulum affects the period of oscillation
pshichka [43]
Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
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3 years ago
How much energy is required to raise the temperature of 5g of air by 10°C?
Alex777 [14]
You need to know the specific heat capacity of air.
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