<h3><u>Answer;</u></h3>
= 64 N/m
<h3><u>Explanation</u>;</h3>
According to Hooke's Law for a helical spring or an elastic material, extensional force is directly proportional to the distance the material has extended.
F = ke; where F is the extension force, k is the spring constant, and e is the distance extended.
Thus;
k = F/e
= 44N/0.69 m
= 63.768 N/m
<u>= 64 N/m</u>
Answer:
Reliability is typically shown as a reliability coefficient created in a calculation to determine the reliability, or consistency, of scores, such as a measure of the amount of consistency between two sets of scores from different administrations from the same group of students.
Answer:k = 10.83 N/m²
Explanation: The angular frequency (ω), spring constant (k) and mass is related by the formulae below
ω = √k/m
But ω = 2πf, where f = frequency.
f = number of oscillations /time taken
Number of oscillations = 14, time taken = 11s
f = 14/11 = 1.27Hz.
ω = 2×22/7×1.27
ω = 7.98 rad/s.
By substituting this parameters into ω = √k/m
Where ω = 7.98rad/s, m = 170g = 170/1000 = 0.17kg.
7.98 = √k/0.17
By squaring both sides
(7.98)² = k/ 0.17
k = (7.98)² × 0.17
k = 10.83 N/m²
Answer:
784 J
Explanation:
Work is force times distance.
W = Fd
W = mgd
W = (40 kg) (9.8 m/s²) (2 m)
W = 784 J
The combination of all of the forces acting on object is net force.
