Answer:
See explanation
Explanation:
We have a mass
revolving around an axis with an angular speed
, the distance from the axis is
. We are given:
![\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]](https://tex.z-dn.net/?f=%5Comega%20%3D%2010%20%5Brad%2Fs%5D%5C%5Cr%3D0.5%20%5Bm%5D%5C%5Cm%3D13%5BKg%5D)
and also the formula which states that the kinetic rotational energy of a body is:
.
Now we use the kinetic energy formula

where
is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:

After replacing in the previous equation we get:

now we have the following:

therefore:

then the moment of inertia will be:
![I = 13*(0.5)^2=3.25 [Kg*m^2]](https://tex.z-dn.net/?f=I%20%3D%2013%2A%280.5%29%5E2%3D3.25%20%5BKg%2Am%5E2%5D)
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:

which can also be rewritten as

(1)
where the labels 1 and 2 mark the initial and final conditions of the gas.
In our problem,

,

and

, so the final pressure of the gas can be found by re-arranging eq.(1):

Therefore the correct answer is
<span>1. 0.75 atm</span>
Answer:
The machine used is called a squaring shear, power shear, or guillotine.
Explanation:
Answer:
9.12267515924 m/s²
Explanation:
Here the moment created by the wheels and the moment created by the center of gravity will balance each other.
h = Height of the center of mass = 78.5 cm
d = Distance from back wheel to the center of mass = 
g = Acceleration due to gravity = 9.81 m/s²
a = Horizontal acceleration
The equation is of the form

The horizontal acceleration of the motorcycle that will make the front wheel rise off the ground is 9.12267515924 m/s²
If we want the object to continue to move at constant speed, it means that the resultant of the forces acting on the object must be zero. So far, we have:
- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.
The resultant of the two forces F1 and F2 is

with direction at

north-west. This means that F3 must be equal and opposite to this force: so, F3 must have magnitude 14.1 N and its direction should be

south-east.