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KatRina [158]
3 years ago
12

Suppose an individual is lying on his stomach with sheets of paper stacked on his back. If each sheet of paper has a mass of 0.0

0350 kg and is the standard letter size of 8.5 in by 11 in ( 0.216 m by 0.279 m ), how many sheets must be stacked to produce a pressure on his back equal to atmospheric pressure (roughly 101325 Pa )
Physics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

N = 177843 sheets

Explanation:

We are given;

Mass;m = 0.0035 kg

Pressure; p = 101325 pa = 101325 N/m²

L = 0.279m

W = 0.216m

The weight of N sheets is N(mg)

Where;

m is the mass of one sheet

N is number of sheets

g is the acceleration due to gravity.

The pressure equals weight divided by the area on which the weight presses:

Thus,

p= F/A = Nmg/(L•W)

Therefore, making N the subject;

N = pLW/(mg)

N = 101325 x 0.279 x 0.216/ (0.0035 x 9.81)

N = 177843

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Answer:

See explanation

Explanation:

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\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]

and also the formula which states that the kinetic rotational energy of a body is:

K =\frac{1}{2}I\omega^2.

Now we use the kinetic energy formula

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After replacing in the previous equation we get:

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now we have the following:

K =\frac{1}{2}m(\omega r)^2 =\frac{1}{2}Iw^2

therefore:

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then the moment of inertia will be:

I = 13*(0.5)^2=3.25 [Kg*m^2]

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3 years ago
A 6.5 l sample of nitrogen at 25◦c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin
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Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
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In our problem, p_1 = 1.5 atm, V_1 =6.5 L and V_2 =13.0 L, so the final pressure of the gas can be found by re-arranging eq.(1):
p_2 = p_1  \frac{V_1}{V_2}= (1.5 atm) \frac{6.5 L}{13.0 L}=0.75 atm

Therefore the correct answer is
<span>1. 0.75 atm</span> 
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3 years ago
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Explanation:

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Vitek1552 [10]

Answer:

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Explanation:

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If we want the object to continue to move at constant speed, it means that the resultant of the forces acting on the object must be zero. So far, we have:
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The resultant of the two forces F1 and F2 is
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