What is the molar ratio of Li to N2 in the given reaction? 6Li + N2 → 2Li3N
2 answers:
Answer: The mole ratio of to
is 6: 1
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
According to the stoichiometry:
6 moles of are combining with 1 mole of
to give 2 moles of
Thus the mole ratio of to
is 6: 1
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Answer:- 1.24 g
Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:
From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.
Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.
we need to convert mL to L, degree C to kelvin and kilopascals to atm.
= 0.495 L
25 + 273 = 298 K
= 1 atm
Ideal gas law equation is:
PV = nRT
We want to find out the n, so let's rearrange this:
R is the universal gas constant and it's value is .
Let's pug in the values in the equation and solve it for n.
n = 0.02 mol
To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.
Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)
= 2.016+12.01+48.00
= 62.03 gram per mol (rounded to two decimal places)
Let's multiply the moles by molar mass:
= 1.24 g
So, the theoretical yield of carbonic acid is 1.24 g.
Answer:
Ka = 1.14x10⁻⁸
Explanation:
First we <u>calculate [H⁺] from the pH</u>:
- pH = -log[H⁺]
- [H⁺] =
- [H⁺] = 6.31x10⁻⁵ M
For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:
- [H⁺] = √(C*Ka)
Where C is the molar concentration of the weak acid solution.
- 6.31x10⁻⁵ M =
- 1.14x10⁻⁸ = Ka