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Paul [167]
3 years ago
15

What were the first 16 elements known in 1760

Chemistry
2 answers:
BartSMP [9]3 years ago
4 0
The discovery of the first basic elements in nature was sufficient to begin the era of industrial revolution through combining two or more of these elements in order to speed up the production processes.

The first discovered elements in nature were:
sulphur
chlorine
argon
neon
carbon
oxygen
helium
silicon
calcium
hydrogen
nitrogen 
sodium
fluorine
lithium
aluminum
Volgvan3 years ago
4 0
<span>This is a simple matter of looking up the discovery date of the elements.  And the results are Known since ancient times Copper, Sulfur, Silver, Tin, Antimony, Gold, Mercury, Lead Then somewhere around 1400, Bismuth. 1669 Phosphorus 1694 Carbon 1735 Iron 1735 Platinum 1751 Nickel, Cobalt 1755 Magnesium The list in alphabetical order is: Antimony, Bismuth, Carbon, Cobalt, Copper, Gold, Iron, Lead, Magnesium, Mercury, Nickel, Phosphorus, Platinum, Silver, Sulfur, and Tin</span>
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Answer:

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8 0
2 years ago
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Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo
Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

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Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

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Step 4: Calculate moles Al2O3

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For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

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Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

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