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andrew11 [14]
3 years ago
15

What is other word for carefully looking at an object or process beginning with the letter O and is 11 letters long

Chemistry
1 answer:
luda_lava [24]3 years ago
5 0
The word is 'Observation'. It fits the given definition, begins with the letter 'O' and is 11 letters long.
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Imagine that instead of balls, you were rolling positively charged ions of the same element).
Ghella [55]
The ion with a +3 charge would be deflected the most by the magnet because it has the strongest positive charge therefore it will be the one being the most repelled. and the ion that would be deflected the least would be the ion with a +1 charge because it has the least amount of charge so the magnet will still repel it but just not as much as it will repel the ion with a +3 charge.

hope that helps
8 0
2 years ago
A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar
Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The  \  mass  \  of  \  the substance}{The   \  Molar  \   Mass   \  of  \   the   \  substance}

Therefore, we have;

The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of  formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³  ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

8 0
2 years ago
Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp
Phantasy [73]

Answer:

a) ^{131}_{53} I

b) ^{192}_{77} Ir

c) ^{153}_{62} Sm

Explanation:

The symbols of the isotopes are written like

^{A}_{Z} X

where,

X is the element

A is the mass number (protons + neutrons)

Z is the atomic number (protons)

<em>a) Iodine-131</em>

The atomic number of iodine is 53. The mass number of this isotope is 131. The symbol is ^{131}_{53} I.

<em>b) Iridium-192</em>

The atomic number of iridium is 77. The mass number of this isotope is 192. The symbol is ^{192}_{77} Ir.

<em>c) Samarium-153</em>

The atomic number of samarium is 62. The mass number of this isotope is 153. The symbol is ^{153}_{62} Sm.

8 0
2 years ago
For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
Salsk061 [2.6K]

The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3                           N = +5                        

O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

     NO2– -----> NO3–

     Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

     NO2– + H2O -----> NO3–

     Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

    NO2– + H2O -----> NO3– + 2H+

     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

3 0
2 years ago
Matter is composed of basic substances called what
Andreyy89
The basic substances are called elements
5 0
3 years ago
Read 2 more answers
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