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Bas_tet [7]
3 years ago
15

The mass of an object is described in ________. a.meters b.cubic meters c.liters d.grams

Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0
The mass of an object is describes in D. Grams.
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A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram
Fiesta28 [93]

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

3 0
3 years ago
Which of the following questions is outside the scope of science?
Airida [17]
A. How religion and philosophy different
All the other choices (b-d) can be explained by science while a can be explain by history I think
4 0
3 years ago
Balance the equation and write the reaction-quotient expression, qc. u(s) + f2(g) ----> uf6(g)
Alona [7]
The equation presented above is that of uranium reacting with fluorine forming uranium fluoride. 

The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
 
                  <em>         U(s) + 3F₂(g) --> UF₆(g)</em>
4 0
3 years ago
Read 2 more answers
After Callie obtained her original results, she wanted to dig deeper. She determined that the germinating corn seed had utilized
Airida [17]

Answer:

Callie expect 600 molecules of CO2 to have been released as a waste during the same amount of time.

Explanation:

During cellular respiration 1 molecule of glucose undergoes oxidation to form 6 molecules of CO2 as a waste product.

     According to the question callie determined that the germinating corn seed had utilized 100 molecules of glucose.

    So 100 molecules of glucose will release 100×6=600 molecules of CO2 as a waste product.

8 0
3 years ago
Read 2 more answers
Consider a situation in which 211 g
Stella [2.4K]

Answer:

3.00 mol

Explanation:

Given data:

Mass of P₄ = 211 g

Mass of oxygen = 240 g

Moles of P₂O₅ = ?

Solution:

Chemical equation:

P₄ + 5O₂       →     2P₂O₅

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 211 g / 123.88 g/mol

Number of moles = 1.7 mol

Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 240 g / 32g/mol

Number of moles = 7.5 mol

Now we will compare the moles of product with reactant.

                       O₂         :         P₂O₅

                        5          :           2

                        7.5       :        2/5×7.5 = 3.00

                       P₄          :         P₂O₅

                        1           :           2

                       1.7         :       2×1.7 = 3.4 mol

Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

Mass of P₂O₅:

Mass = number of moles × molar mass

Mass = 3 mol ×283.9 g/mol

Mass = 852 g

3 0
3 years ago
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