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Drupady [299]
3 years ago
9

Which best describes the purpose of a controlled experiment?

Physics
1 answer:
navik [9.2K]3 years ago
3 0
A controlled experiment is best described as a safe, in depth, and insightful display that helps you understand the purpose of the experiment better
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Radda [10]

Answer:

the rotation of earth is determining what part of the sun faces what part of earth making time the part thats away from the sun would be night and the one facing the sun itself would be day

6 0
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Find the magnitude of the sum<br> of these two vectors:<br><br> 101 m<br> 60.0 °<br> 85.0 m
attashe74 [19]

Answer: 161.3

I have a acellus too and got this question correct, so I hope this helps y’all out

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3 years ago
Find the total electric charge of 1.7 kg of electrons. me=9.11×10−31kg, e=1.60×10−19C.
Gelneren [198K]

Answer:

2.99\cdot 10^{11}C

Explanation:

The mass of one electron is

m_e = 9.11\cdot 10^{-31}kg

So the number of electrons contained in M=1.7 kg of mass is

N=\frac{M}{m_e}=\frac{1.7 kg}{9.11\cdot 10^{-31}kg}=1.87\cdot 10^{30}

The charge of one electron is

e=1.60\cdot 10^{-19} C

So, the total charge of these electrons is equal to the charge of one electron times the number of electrons:

Q=Ne=(1.87\cdot 10^{30})(1.6\cdot 10^{-19}C)=2.99\cdot 10^{11}C

8 0
3 years ago
HELP ASP PLEASED AND THANKS NO LINKS PLEASED AND NO FILES
SOVA2 [1]

Answer:

just search up a ven-diagram and then try to draw it or trace it then use it for ur question

Explanation:

6 0
3 years ago
Lucia kicks a ball on a level playing field with an initial velocity of 11.3 m/s at an angle of 35° above the horizontal. Find:
grandymaker [24]

Explanation:

Given that,

Initial velocity, u = 11.3 m/s

Angle above the horizontal, \theta=35^{\circ}

Time of flight :

t=\dfrac{2u\sin\theta}{g}\\\\t=\dfrac{2\times 11.3\times \sin(35)}{9.8}\\\\t=1.32\ s

Horizontal distance traveled  is given by :

x = ut

x = 11.3 m/s × 1.32 s

x = 14.916 m

Maximum height is given by :

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(11.3)^2\times \sin^2(35)}{2\times 9.8}\\\\H=2.14\ m

Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.

6 0
3 years ago
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