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miss Akunina [59]
3 years ago
11

HAaaaaaaaaaaaLPPP thank you.

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0
15 guesting i think it not right
Nataly [62]3 years ago
5 0

mass of product= 40 +23= 63 grams

Explanation:

we use the law of conservation of mass which says that mass can neither be created and nor destroyed.So sum of mass of all the reactants is equal to the sum of mass of all the products.

Here sum of mass of reactants= 40+23= 63 grams

so the mass of products=63 grams

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How are velocity and displacement related?
Keith_Richards [23]

Velocity is the rate at which displacement changes with time. It is a vector, too. The average velocity over some interval is the total displacement during that interval, divided by the time. ... Speed is a scalar, which describes the total distance travelled by some object during some time interval. Plze mark me brainiest

7 0
3 years ago
A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture i
MArishka [77]

Answer:

500 g

Explanation:

Specific heat of water = 1 j/g-c

Heat given up by hot water = 200(75-25)(1) = 10 000 j

this is the heat GAINED by the cold water

10000 j =  x ( 25 -5)(1)  

          x =500g

3 0
2 years ago
PSYW - Please Show Your Work
Ad libitum [116K]

Answer:

9.66E4 J

Explanation:

7 0
3 years ago
When objects are heated they tend to expand because
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5 0
3 years ago
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
3 years ago
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