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3 years ago

HAaaaaaaaaaaaLPPP thank you.

Physics

2 answers:

lara31 [8.8K]3 years ago

7 0

15 guesting i think it not right

Nataly [62]3 years ago

5 0

mass of product= 40 +23= 63 grams

Explanation:

we use the law of conservation of mass which says that mass can neither be created and nor destroyed.So sum of mass of all the reactants is equal to the sum of mass of all the products.

Here sum of mass of reactants= 40+23= 63 grams

so the mass of products=63 grams

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The windowpanes are___________ a. opaque b. transparent c. absorbent .

kogti [31]

Answer:

The windowpanes are- transparent.

The color of the panes are due to the wavelengths of light that the glass- allows to pass through

Explanation:

Just answered the question.

4 0

3 years ago

Read 2 more answers

What are the names of the 2 charged particles in an atom and what are their charges

Sholpan [36]

Answer:

Protons and electrons

Explanation:

The atoms are made up of protons, neutrons, and electrons.
The physical and chemical characteristics of an atom are determined by the number of these particle composition.
The protons present in the center of an atom called the nucleus is positively charged.
The neutrons are also located in the nucleus of an atom with no charge.
The electrons has a negative charge and it is placed around the nucleus having different shells and quantum state.
The charges of the protons and electrons are denoted by +q and -q. The quantization of these charges are +1, +2, ... and -1, -2, .... etc.

3 0

3 years ago

A wire, 1.0 m long, with a mass of 90 g, is under tension. A transverse wave is propagated on the wire, for which the frequency

Mice21 [21]

Answer:

T = 712.9 N

Explanation:

First, we will find the speed of the wave:

v = fλ

where,

v = speed of the wave = ?

f = frequency = 890 Hz

λ = wavelength = 0.1 m

Therefore,

v = (890 Hz)(0.1 m)

v = 89 m/s

Now, we will find the linear mass density of the wire:

$\mu = \frac{m}{L}$

where,

μ = linear mass density of wie = ?

m = mass of wire = 90 g = 0.09 kg

L = length of wire = 1 m

Therefore,

$\mu = \frac{0.09\ kg}{1\ m}$

μ = 0.09 kg/m

Now, the tension in wire (T) will be:

T = μv² = (0.09 kg/m)(89 m/s)²

7 0

3 years ago

What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?

Vlada [557]

Answer:

$Ep=-2.3*10^{-19}J$

Explanation:

The change in potential energy can be expressed as:

$Ep=K.\frac{q1.q2}{r}$

where K is a constant with a value of $9*10^{9}\frac{N.m^{2}}{C^{2}}$ , q1 and q2 are the charges of the proton and the electron and r is the distance between them.