Answer:
The average force on ball by the golf club is 340 N.
Explanation:
Given that,
Mass of the golf ball, m = 0.03 kg
Initial speed of the ball, u = 0
Final speed of the ball, v = 34 m/s
Time of contact, 
We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

So, the average force on ball by the golf club is 340 N.
Hooke's Law
F = k. Δx
Δx = 30 cm = 0.3 m
200 = k . 0.3

the spring stretch for 100 N:

Answer:
Explanation:
Given
Initial Moment of Inertia 
initial Spin 

Final Moment Moment of Inertia 
Conserving Angular momentum




