Does data from mass spectrometry indicate that modern scientists have made modifications to Dalton's model?

Chemistry

1 answer:

Viktor [21]3 years ago

8 0

$http://apchemresources2014.weebly.com/uploads/9/7/6/4/9764824/mass_spectrometry.pdf$

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dezoksy [38]

Answer:

.00196 g/ml

Explanation:

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4 years ago

If on substance has 9 positive charges and 11 negative charges is it positive or negative

Bingel [31]

Answer:

Negative.

Explanation:

The nine positive charges can cancel with nine of the negative charges leaving only two negative charges, which makes it negative.

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3 years ago

Borax (na2b4o7Â·10h2o; fw = 381.372 g/mol; density = 1.73 g/ml), a primary standard, was used to standardize a solution of hno3.

SashulF [63]

<span>0.06355391 mol The balanced equation for the reaction is Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O So for each mole of Borax to neutralize, it takes 2 moles of HNO3. Calculate number of moles of Borax 0.2619 g / 381.372 g/mol = 0.0006867 mol Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So 0.0013734 / 0.02161 = 0.06355391 mol</span>

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4 years ago

Period table review i need help due on tomorrow help I will post the???

amm1812

What's the question I don't get it?

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3 years ago

How much heat is transferred when 7.19 grams of H2 reacts with excess nitrogen, according to the following equation: N2(g) + 3 H

nikdorinn [45]

Answer:

$Q=54.8kJ$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

$\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}$

Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:

$Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ$

Best regards!

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3 years ago