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Karolina [17]
3 years ago
15

What mass will 33.6 l of chlorine gas (cl2) have at stp

Chemistry
1 answer:
Aloiza [94]3 years ago
5 0
The STP stands for standard temperature and pressure which means in a condition where the temperature is 273.15K and the pressure is 0.986atm. In STP, an ideal gas will have a volume 22.4 liters for every mol of gas. Then, the amount of molecule of the <span>33.6 l of chlorine gas (Cl2) would be:

volume of gas/ number of mol=  22.4l/mol
</span>33.6l/ number of mol=  22.4l/mol
<span>number of mol= 33.6l / (22.4 liters/mol)= 1.5 moles

The mass of the gas would be: 1.5 moles * </span><span>70.906 </span>g/mol= 106.359 grams
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<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

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In the question that:

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On putting these values in the above equation, we get

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To know more about moles, visit the below link:

brainly.com/question/15374113

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