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lianna [129]
3 years ago
15

Members of a species can mate with each other and produce

Chemistry
1 answer:
Georgia [21]3 years ago
6 0
Fertile offspring mate is a form of reproduction
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What is the relationship between chemical and electrical energy
soldi70 [24.7K]

Answer:

Electrochemistry,

Explanation:

Electrochemistry is a branch of chemistry concerned with the relation between electricity and chemical change. Many spontaneously occurring chemical reactions liberate electrical energy, and some of these reactions are used in batteries and fuel cells to produce electric power.

I Hope This Helps!!!!!

4 0
3 years ago
Read 2 more answers
1. How much heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C?
diamong [38]

Answer: An amount of 40980.48 J/g^{o}C heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Explanation:

Given: mass of lead = 4.64 kg

Convert kg into grams as follows.

1 kg = 1000 g\\4.64 kg = 4.64 kg \times \frac{1000 g}{1 kg}\\= 4640 g

T_{1} = 150^{o}C

T_{2} = 219^{o}C

The standard value of specific heat of lead is 0.128 J/g^{o}C.

Formula used to calculate heat is as follows.

q = m \times C \times \Delta T

where,

q = heat energy

m = mass of substance

C = specific heat of substance

\Delta T = change in temperature

Substitute the value into above formula as follows.

q = m \times C \times \Delta T\\= 4640 g \times 0.128 J/g^{o}C \times (219 - 150)^{o}C\\= 40980.48 J/g^{o}C

Thus, we can conclude that 40980.48 J/g^{o}C heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

8 0
3 years ago
A balloon is inflated with helium to a volume of 45L at room temperature (298K). If the balloon is cooled to 200.K, what is the
igor_vitrenko [27]

Answer:

V₂ = 30.20 L

Explanation:

Given data:

Initial volume = 45 L

Initial temperature = 298 K

Final temperature = 200 K

Final volume = ?

Solution;

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 45 L × 200 K / 298 k

V₂ = 9000 L.K / 298 K

V₂ = 30.20 L

8 0
3 years ago
What is the equation for the acid dissociation constant, Ka, of HF?
VashaNatasha [74]

Answer:

hydrofluoric acid HF H+ + F- 7.2 × 10-4

4 0
3 years ago
In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid sodium nitrate must be use
GarryVolchara [31]

The grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

According to the definition of molar concentration of a substance dissolved in a solution is defined as the ratio of the number of moles to the volume of the solution.

C = n/V

The number of moles is equal to the given mass divided by the molar mass.

n = m/Mm = n ×m

Given,

The volume of the solution of copper oxide = 0.53

Molar mass of copper oxide = 79.5

Concentration of copper oxide = 0.125

CuO = cVM

= 0.125 × 0.53 × 79.5

= 5.26g

Thus, we concluded that the grams of solid copper oxide must be used to prepare a solution of 0.125m concentration is 5.26 g.

DISCLAIMER: The above question is wrong. The correct question is

Question: In lab you have to prepare 530. 00 ml solution of 0. 125 m copper (ii) oxide. How many grams of solid copper oxide must be used to prepare a solution of this concentration?

learn more about molar concentration :

brainly.com/question/14803618

#SPJ4

3 0
1 year ago
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