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kvv77 [185]
3 years ago
6

A chemist prepares a solution of silver(I) nitrate by measuring out of silver(I) nitrate into a volumetric flask and filling the

flask to the mark with water.
Chemistry
1 answer:
leva [86]3 years ago
4 0

Answer:

3.33 M

Explanation:

It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:

" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>

<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "

In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:

  • 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃

Then we<u> convert the 150 mL of the volumetric flask into L</u>:

  • 150 / 1000 = 0.150 L

Finally we <u>divide the moles by the volume</u>:

  • 0.500 mol AgNO₃ / 0.150 L = 3.33 M
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6) A 14.5 g sample of sodium chloride reacts with excess fluorine gas according to
Ann [662]

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

  • <em>mass of the sodium chloride, = 14.5 g</em>
  • <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>

<em />

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of  Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl -------------------  ?

= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g

Learn more here:brainly.com/question/8470145

8 0
3 years ago
The half-life of carbon-14 is 5730 years. How many grams of carbon-14 remain after 28,650 years if the original amount was 28.0
alexdok [17]
TLDR: the answer is C. 0.875.

The basis of this problem is testing your fluency with half-life radioactive decay. The half-life of any radioactive substance represents the amount of time required for 1/2 of the amount of the substance to decay. So, if you had a 100 g sample of Carbon-14, after 5,730 years, only 50 g of Carbon-14 would remain; the other 50 g of substance would have decayed into another substance (Nitrogen-14). If another 5,730 years passes, only 25 g would remain, as half of that 50 g radioactive substance would have decayed.

In the problem, 28 g of Carbon-14 decays as 28,650 years passes, which, when divided by 5,730, yields a value of 5. This number represents the number of half lives that passes during this time. So, over the course of this time, the amount of radioactive substance is cut in half five times.

28 g - 14 g (1 HL) - 7 g (2 HL) - 3.5 (3 HL) - 1.75 g (4 HL) - 0.875 g (5 HL)

After 5 half lives, only 0.875 g of the original 28 g remains.
5 0
3 years ago
Lithium sulphate is used in some medicines and its presence in a medicine can be shown by two a combination of two tests a)expla
shtirl [24]

Answer:

A flame test could help by seeing what things it could catch on fire from or the things that could happen with acids etc. I would test the medicine by asking someone who has had it in their life, asking doctors or I would maybe use it myself maybe. (I don’t know about c, sooo sorry)

6 0
3 years ago
Tell me the stupidest story and it has to be funny. The funniest gets brainliest and a thanks +5 stars!
guapka [62]

Answer ill message you one

Explanation:

7 0
3 years ago
Which radioisotope is a beta emitter?(1) 90Sr (3) 37K(2) 220Fr (4) 238U
Ulleksa [173]
The answer is (1) 90 Sr. The definition of beta decay is that a type of radioactive decay in which one proton will change to one neutron and release one electron inside the nucleus. And 90Sr is a common beta emitter.
4 0
3 years ago
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