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forsale [732]
3 years ago
11

Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou

ld the dry gas occupy at standard conditions? (hint: consider dalton's law of partial pressures.)
Chemistry
1 answer:
lesya [120]3 years ago
3 0
First, let's compute the number of moles in the system assuming ideal gas behavior. 

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>
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Answer:

4 moles

Explanation:

A mole is equal to 6.02214076 × 1023 of any chemical unit (atoms, molecules, ions)

To find number of moles in 89 litres of water vapor use the following formula:

1 mole = 22.4 L

That is 1 L = \frac{1}{24} mole

Volume of water vapor = 89 litres

Therefore,

Number of moles in 89 litres = \frac{89}{24}=3.7 ≈ 4 moles

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