Answer:
v = a/√(2h/g) m/s
Explanation:
Lets say the distance away from the cliff is a.
then, a = v t
where v is velocity with which it was thrown and t is time taken to fall.
Using equations of motion, we can also say that
h=1/2gt^2
where h is the height of the cliff
Thus, t^2 = 2h/g and t = √(2h/g)
Thus, v = a/√(2h/g).
the vehicle was pushed off the cliff with the velocity , v = a/√(2h/g). m/s
