Answer:
2210.91 N
Explanation:
f = v/∧ = 1/2 √ T/ μ
where f= 28.1 Hz , T= tension ,
L= 2m
mass density = μ = 350÷1000/2.00
= 0.175kg/m
from f = 1/2L √ T/ μ
make T the subject of the formula
T= (f×2L)² ₓ μ
T= (28.1×2×2)² ×0.175
T=12633.76×0.175
=2210.91 N
Answer:
11 or 10 meters a second
Explanation:
pretty sure thats my explanation "pretty sure" like my confidence? mark me brainliest bad at spelling lol
Answer:
Explanation:
Tension T in the rope will create torque in solid cylinder ( axle ). If α be angular acceleration
T R = 1/2 M R²α ( M is mass and R is radius of cylinder )
= 1/2 M R² x a / R ( a is linear acceleration )
T = Ma / 2
For downward motion of the bucket
mg - T = m a ( m is mass and a is linear acceleration of bucket downwards )
mg - Ma / 2 = ma
a = mg / ( M /2 + m )
Substituting the values
a = 14.7 x 9.8 / ( 5.8+ 14.7 )
= 7 m / s²
A )
T = Ma / 2
= 5.8 x 7
= 40.6 N
B ) v² = u² + 2 a h
= 2 x 7 x 10.3
v = 12 m /s
C )
v = u + a t
12 = 0 + 7 t
t = 1.7 s
Answer:
C) Pnew=Poriginal/9
Explanation:
From the given conditions:
Original area, 
New area of the barrel bottom panel after increasing by a factor of 3:

On increasing the radius the area now becomes:


As we know that there will be no increase in the down-force since the height remains constant.
Pressure is given as:

∴New pressure:


The spring constant is 66.7 N/m
Explanation:
First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:

where:
m = 0.50 kg is the mass of the object
is the acceleration of gravity
Substituting,

Now we can use Hookes' law to find the constant of the spring:

where
F is the force applied
k is the spring constant
x is the stretching of the spring
Here we have:
F = 5 N
While the stretching is
x = 0.075 m
Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:

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