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kari74 [83]
3 years ago
5

How many milliliters of 6.00 m hcl(aq) are required to react with 7.65 g of zn(s)?

Chemistry
1 answer:
Solnce55 [7]3 years ago
7 0
The  number  of  ml  of  hcl  required  to  react  with  Zn  is  calculated  as  follows
step  one:  calculate the  number  of  Zn   moles
that  is  mass/  molar  mass  of  Zn
7.65  g/65.38  g /mol=  0.117  moles

step  two :  write  the  reacting  equation
Zn  +  2  HCl --->  ZnCl2  +  H2
from  the  equation   above  the  reacting  ratio   between  ZN  to  HCl  is  1:2
therefore  the  moles  of  HCL  =  2  x  0.117moles =  0.234  moles

volume  of  Hcl=  moles of  HCl  /  molarity  of  Hcl
that  is   0.234 /6=0.039 L  ,  multiply  by  1000  to  convert  to  Ml  since  molarity  is  the  concentration  in  litres
0.039  x1000=  39ML
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