<u>Answer:</u> The heat of formation of oleic acid is -94.12 kJ/mol
<u>Explanation:</u>
We are given:
Heat of combustion of oleic acid =
The chemical equation for the combustion of oleic acid follows:
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as
The equation used to calculate enthalpy change is of a reaction is:
The equation for the enthalpy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the heat of formation of oleic acid is -94.12 kJ/mol
Hey there!
The answer/answers: <span>The four main greenhouse gases that support the natural greenhouse effect are:
</span><span>H2O (water vapor)
CO2 (carbon dioxide)
CH4 (methane)
and
NO (nitrous oxide)
These</span><span> greenhouse gas traps heat from the sun
</span>
Hopes this Helps u :D
<span>
</span>
Answer:
water and air
Explanation:
The examples of medium from this problem is water and air.
A medium is an agency or a means of propagating energy, waves or even facilitating a chemical reaction.
Fluids are very good medium in chemistry for chemical reactions. The two most common media used are air and water.
In physics, a vacuum is an empty space that has been evacuated. It also serves as a medium to study some physical phenomenon.
beacuse bromine is more reactive than iodine.
Answer:
Attached below
Explanation:
Attached below is the required diagrams
From the attached diagram ; Compounds 1 and 2 are achiral ( i.e. stereoisomers aren't possible here )
Compound 3 : ( 1S, 2R ) - 1 - chloro-2-methylcyclopropane
Compound 4: ( 1R , 2S ) - 1- chloro-2-methylcyclopropane
Compound 5: ( 1R, 2R ) - 1 - chloro-2-methylcyclopropane
Compound 6: ( 1S, 2S ) -1- chloro-2- methyl cyclopropane