The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.
<u>Answer:</u> The correct answer is saturated solution.
<u>Explanation:</u>
For the given options:
Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.
Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.
Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent. The concentration of the solute particles that can be dissolved in a solution is maximum.
Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.
From the above information, we conclude that the given solution is saturated solution.
Answer: The frequency of this light is 
Explanation:
To calculate the wavelength of light, we use the equation:
where,
= wavelength of the light =
c = speed of light = 
= frequency of light = ?
The frequency of this light is
Answer:
6.67 M
Explanation:
Molarity = 
<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>
200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH
750 mL x (1 L/1000 mL) = 0.750 L
<em>Substitute values into the equation.</em>
Molarity = 
Molarity = 6.667... M
Molarity = 6.67 M
