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olga55 [171]
3 years ago
11

Using the ideal gas law, PV=nRT, where R=0.0821 L atm/mol K, calculate the volume in liters of oxygen produced by the catalytic

decomposition of 25.5 g potassium chlorate according to the following reaction. The oxygen is collected at 2.22 atm and 25.44 C. express your answer to the correct number of significant figures.
2KClO3(s) ---> 2KCl(s) + 3O2(g)
Chemistry
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

V = 2.32 Liters

Explanation:

PV = nRT => V = nRT/P

n = 25.8g/122g/mole = 0.21 mole

R = 0.08206 L·atm/mol·K

T = 25.44°C + 273 = 298.44K

P = 2.22 atm (given in problem)

V = (0.21mol)(0.08206 L·atm/mol·K)(298.44K)/(2.22atm) = 2.32 Liters at 25.44°C & 2.22atm

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See the answer below , please.

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Then we have 5.00g of H2O2=5/34.0148=0.146995
As you know decomposition of 2moles now has prodused <span>196kj
So, </span><span>q is made due </span>0.146995 moles of H2O2=(-196/2)*0.146995=-14.40551Kj
I'm sure it will help.
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