Answer:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.
The values of t are <u>4.643 second</u> for the function 
What is batter misses?
An out in baseball happens when the umpire declares a batter or baserunner out. A hitter or runner who is out is no longer able to score runs and must go back to the dugout until their subsequent turn at bat. The batting team's turn is over after three outs are recorded in a half-inning.
In order to signal an out, umpires typically make a fist with one hand and then flex that arm, either upward on pop flies or forward on regular plays at first base. To indicate a called strikeout, home plate umpires frequently use a "punch-out" action.When a batter is struck by a pitched ball without making a swing at it, it is referred to as a hit-by-pitch. He consequently gets first base.
We have been given that
s = 6 feet
v = 73 feet per second
Substituting these values in the formula 

When the ball hits the ground, the height becomes zero. Thus, H(t)=0

We solve the equation using quadratic formula 
Substituting the values a=-16, b= 73, c=6

Learn more about the batter misses with the help of the given link:
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Try this solution (if it is possible, check it in other sources):
1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

3. According to the formula of the Speed:
Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)
Answer: 6.84 (m. per sec.)
Answer:
B) Bb × Bb I think I can't promise that's right
'D' is one way to increase the current. Another way is to increase the voltage. / / / It's possible that 'C' might also be a true statement. We don't know; because we can't see it.