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nydimaria [60]
3 years ago
5

Describe the sequence of events in the lithification of a sandstone

Physics
2 answers:
guajiro [1.7K]3 years ago
6 0
Lithification is a diagenetic process in which loose sediment is converted to hard rocky compaction and cementation. So sediments (sand) are buried the increase in pressure from the weight of the overlaying material pushes the grains closer together. The volume of sediment is reduced and the fluids between the grains are also squeezed out. This leaves the sandstone tightly compressed <span>together this is lithification.</span>
Strike441 [17]3 years ago
5 0
<h3><u>Answer and explanation;</u></h3>
  • <em><u>Lithification refers to the process that involves compacting, sedimentation and cementing of the mass together under pressure to create a sand stone, a form of sedimentary rock.</u></em>
  • <em><u>Weathering and erosion of rocks creates sediments </u></em>which collect and are then moved to another location.
  • <em><u>At some point the sediment may become heavy for the agent such as water to carry and thus deposited. </u></em>As this deposit thickens, it becomes heavier and thus lithification process start.
  • <em><u>Compaction forces</u></em> the grains of the deposited sediments closer together, forcing out air and water.
  • <em><u>As a result of compaction the sediment's pores becomes smaller. Minerals deposit in these pores as the water squeezes out. </u></em>As the water moves out the pressure increases, the mineral deposits start hardening thus cementing the entire mass and this results to a sand stone.
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A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, co
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Answer:

Current: 1.0 Amperes

The minimum current is flowing through path D

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We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:

\frac{1}{R_e} =\frac{1}{R_B}+\frac{1}{R_C}+\frac{1}{R_D}\\\frac{1}{R_e} =\frac{1}{10}+\frac{1}{20}+\frac{1}{50}=0.17\\R_e=(1/0.17)\Omega\\R_e=5.88 \Omega

with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:

V=I*R\\6V=I*5.88\Omega\\I=\frac{6}{5.88} Amp\\I=1.02A

where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.

The current will be the lowest through the branch with the largest resistor due to the fact that less current will flow through the path of more resistance.

Than means that the lowest current will be registered through branch D where the 50 \Omega resistor is.

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An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v.  The rms current will be  8.54 A

AC stands for “Alternating Current,” meaning voltage or current that changes polarity or direction, respectively, over time. AC electromechanical generators, known as alternators, are of simpler construction than DC electromechanical generators.

RMS or root mean square current/voltage of the alternating current/voltage represents the D.C current/voltage that dissipates the same amount of power as the average power dissipated by the alternating current/voltage. For sinusoidal oscillations, the RMS value equals peak value divided by the square root of 2.

I (RMS) = RMS voltage / \sqrt{R^{2}+ X_{L} { ^{2}  }

           =  442 / \sqrt{29.4^{2} + 42.6^{2}  }

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To learn more about Alternating Current here

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