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nydimaria [60]
3 years ago
5

Describe the sequence of events in the lithification of a sandstone

Physics
2 answers:
guajiro [1.7K]3 years ago
6 0
Lithification is a diagenetic process in which loose sediment is converted to hard rocky compaction and cementation. So sediments (sand) are buried the increase in pressure from the weight of the overlaying material pushes the grains closer together. The volume of sediment is reduced and the fluids between the grains are also squeezed out. This leaves the sandstone tightly compressed <span>together this is lithification.</span>
Strike441 [17]3 years ago
5 0
<h3><u>Answer and explanation;</u></h3>
  • <em><u>Lithification refers to the process that involves compacting, sedimentation and cementing of the mass together under pressure to create a sand stone, a form of sedimentary rock.</u></em>
  • <em><u>Weathering and erosion of rocks creates sediments </u></em>which collect and are then moved to another location.
  • <em><u>At some point the sediment may become heavy for the agent such as water to carry and thus deposited. </u></em>As this deposit thickens, it becomes heavier and thus lithification process start.
  • <em><u>Compaction forces</u></em> the grains of the deposited sediments closer together, forcing out air and water.
  • <em><u>As a result of compaction the sediment's pores becomes smaller. Minerals deposit in these pores as the water squeezes out. </u></em>As the water moves out the pressure increases, the mineral deposits start hardening thus cementing the entire mass and this results to a sand stone.
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A cold front moves through and the temperature drops by 20 degrees. in which temperature scale would this 20 degree change repre
nalin [4]
In the Celsius scale each degree is one part of 100 degrees. This is because in this scale the difference between boiling and freezing temperatures of water is 100 ° - 0 ° = 100 °, so one degree Celsius is one part of 100.

In the Farenheit scale, each degree is one part of 180 degrees. This is because in this scale the difference between the boiling and freezind temperatures are 212 ° - 32 ° = 180°, so one degree Farenheti is one part of 180.

That means that 1 °C is a larger amount than 1 °C, so 20°C is a larger amount than 20°F.

Conclusion: 20 degree change represents a larger change in Celsius scale.

4 0
3 years ago
A skateboarder is skating back and forth on the halfpipe as seen below. As he skates his energy transforms from potential energy
egoroff_w [7]

Answer:

Friction and air resistance cause some of his kinetic energy to be “lost”. This makes him slow down.

Explanation:

The law of conservation of energy states that in absence of frictional forces, the mechanical energy of an object (given by the sum of its kinetic and potential energy) is conserved. In such a situation, the skateboarder would never stop his motion, because potential energy is continuously converted into kinetic energy and vice-versa, but the total energy remains the same so he would never stop.

In a real world, however, this is not true. In fact, in a real world some frictional force are present, in particular:

- friction: this force is due to the contact between the skateboard and the surface of the halfpipe, and its direction is always opposite to the motion of the skateboarder

- Air resistance: this force is due to the resistance opposed by the molecules of air that the skateboarder meets during his motion, and its direction is also opposite to the motion of the skateboarder

This two forces are said to be non-conservative forces, which means that they cause some of the mechanical energy of the skateboarder to be "lost", in the sense that it is dissipated as heat and it is no longer available for the skateboarder.

Therefore, the correct option is

Friction and air resistance cause some of his kinetic energy to be “lost”. This makes him slow down.

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3 years ago
In a simple electric circuit, ohm's law states that v=irv=ir, where vv is the voltage in volts, ii is the current in amperes, an
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We take the derivative of Ohm's law with respect to time: V = IR
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We are given that voltage is decreasing at 0.03 V/s, resistance is increasing at 0.04 ohm/s, resistance itself is 200 ohms, and current is 0.04 A. Substituting:
-0.03 V/s = (0.04 A)(0.04 ohm/s) + (200 ohms)(dI/dt)
dI/dt = -0.000158 = -1.58 x 10^-4 A/s
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