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4 years ago

14

Fluid in the semicircular canals stimulates impulses to the brain to maintain balance t or f

1 answer:

bazaltina [42]4 years ago

7 0

The answer is True. Fluid in the semicircular canals stimulates impulses to the brain to maintain balance. <span>If the semicircular canals are damaged, the balance sense will be affected. </span>

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The reason that elements in the same group all have similar chemical properties is because they all have the same

sveta [45]

D-number of electrons in the outer energy level.

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4 years ago

What is the ph of a buffer prepared by adding 0.809 mol of the weak acid ha to 0.608 mol of naa in 2.00 l of solution? The disso

Anarel [89]

The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

$pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247$

The pH of the buffer can be known as

$pH = pK_{a} + log[\frac{[A-]}{[HA]}}]$

The concentration of $[A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\$

Similarly, the concentration of [HA] = $\frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404$

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

$pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236$

So, the pH of the buffer is 6.1236.

5 0

4 years ago

Which situation is appropriate for using rate laws?

alukav5142 [94]

The answer is: To see how fast hydrogen peroxide decomposes into water and oxygen.
Hope I helped god bless U ;)

8 0

4 years ago

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If an experiment calls for 0.200mole acetic acid (Hc2H3O2)how many grams of glacial acetic acid do we need?

bija089 [108]

<h3>Molar mass:-</h3>

$\\ \sf\longmapsto HC_2H_3O_2$

$\\ \sf\longmapsto 1u+2(12u)+3(1u)+2(16u)$

$\\ \sf\longmapsto 1u+24u+3u+48u$

$\\ \sf\longmapsto 28u+48u$

$\\ \sf\longmapsto 76u$

$\\ \sf\longmapsto 76g/mol$

No of moles=0.2mol
Given mass=?

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}$

$\\ \sf\longmapsto 0.2=\dfrac{Given\:mass}{76}$

$\\ \sf\longmapsto Given\:Mass=0.2\times 76$

$\\ \sf\longmapsto Given\:Mass=1.52g$

7 0

4 years ago

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O

timofeeve [1]

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

Zn +HNO3➔Zn(NO3)2+NO+H2O

step 2: identity undergoing oxidation or reduction

here

Zn➔Zn(NO3)2

Zn is oxidized from 0 to 2 in oxidation no.

HNO3➔NO

N is reduced from 5 to 2 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Zn=0-2=-2=2

in

N=5-2=3

Step 4: Balance it by doing crisscrossed multiplication

we get;

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

step 6:Balance other atoms except H & O

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O

finally: balance H

<em><u>3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O</u></em>

3 0

3 years ago

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