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2 years ago

2. What does the diamond-shaped symbol stand for in a consumer product label?

Chemistry

1 answer:

Nikitich [7]2 years ago

4 0

The red diamond represents the potential hazards that are associated with the product.

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6. What does the symbol AH stand for?

Vesnalui [34]

the heat of reaction for a chemical reaction

4 0

3 years ago

Write the net ionic equation for the reaction of aqueous copper(II) chloride with aqueous sodium phosphate. Remember to include

sergeinik [125]

Answer:

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

Explanation:

Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.

3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)

The complete ionic equation includes all the ions and insoluble species.

3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

7 0

2 years ago

What is my formula? Silver l acetate

Nutka1998 [239]

Answer:

Ag(I)C2H3O2 ....................

Silver only has a single valence value (+1) so you really don't need to put the (I) in the chemical formula.

7 0

2 years ago

The density of ice is 917 kg/m3. The density of salt water is 1029 kg/m3. A mass of ice is 2.55 x 1013 kg. Calculate the volume

Ksju [112]

Answer:

Volume of salt water, $V_{sw} = 247.74 km^3$

Explanation:

Density of Ice, $\rho_{ice} = 917 kg/m^3$

Density of salt water, $\rho_{sw} = 1029 kg/m^3$

Volume of ice, $V_{ice} = 278 km^3$

Volume of salt water, $V_{sw} = ?$

Mass = Density * Volume

Mass of Ice, $m_{ice} = \rho_{ice}V_{ice}$

Mass of Salt water, $m_{sw} = \rho_{sw}V_{sw}$

Since , $m_{ice} = m_{sw}$

$\rho_{ice}V_{ice} = \rho_{sw}V_{sw}\\\\(917*278) = (1029*V_{sw})\\\\V_{sw} = \frac{254926}{1029} \\\\V_{sw} = 247.74 km^3$

5 0

3 years ago

A chemist requires 5.00 liters of 0.420 M H2SO4 solution. How many grams of H2SO4 should the chemist dissolve in water? 129 gram

natali 33 [55]

Answer:

Approximately 206 grams.

Explanation:

How many moles of sulfuric acid $\mathrm{H_2SO_4}$ are there in this solution?

$\text{Number of moles of solute} = \text{Concentration} \times \text{Volume}$ .

The unit for concentration " $\mathrm{M}$ " is equivalent to mole per liter. In other words, $\rm 1\;M = 1\; mol\cdot L^{-1}$ . For this solution, the concentration of $\mathrm{H_2SO_4}$ is $\rm 0.420\;M = 0.420\; mol\cdot L^{-1}$ .

$\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V\\&= \rm 0.420\;mol\cdot L^{-1}\times 5.00\; L \\&= \rm 2.10\; mol\end{aligned}$ .

What's the mass of that $\rm 2.10\; mol$ of $\mathrm{H_2SO_4}$ ?

Start by finding the molar mass $M$ of $\mathrm{H_2SO_4}$ .

Relative atomic mass data from a modern periodic table:

H: 1.008;
S: 32.06;
O: 15.999.

$\displaystyle M(\mathrm{H_2SO_4}) = 2\times \underbrace{1.008}_{\mathrm{H}} + 1\times \underbrace{32.06}_{\mathrm{S}} + 4\times \underbrace{15.999}_{\mathrm{O}} = \rm 98.072\;g\cdot mol^{-1}$ .

$\text{Mass} = \text{Quantity in moles} \times \text{Molar Mass}$ .

$m = n \cdot M = \rm 2.10\; mol \times 98.072\;g\cdot mol^{-1} \approx 206\; g$ .

In other words, the chemist shall need approximately 206 grams of $\mathrm{H_2SO_4}$ to make this solution. As a side note, keep in mind that the 206 grams of $\mathrm{H_2SO_4}$ also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.

6 0

3 years ago