All categories

3 years ago

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O

Chemistry

2 answers:

Westkost [7]3 years ago

6 0

Answer:

Your ans is in the picture.

timofeeve [1]3 years ago

3 0

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

Zn +HNO3➔Zn(NO3)2+NO+H2O

step 2: identity undergoing oxidation or reduction

here

Zn➔Zn(NO3)2

Zn is oxidized from 0 to 2 in oxidation no.

HNO3➔NO

N is reduced from 5 to 2 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Zn=0-2=-2=2

N=5-2=3

Step 4: Balance it by doing crisscrossed multiplication

we get;

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

step 6:Balance other atoms except H & O

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O

finally: balance H

3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O

You might be interested in

How many moles of silver are in 8.46E24 atoms of silver?

KonstantinChe [14]

Answer:

14.048 moles I believe.

Explanation:

(8.46 * 10^24) / ( 6.022 * 10^23) = 14.048

6 0

2 years ago

Which of these expressions are correct variations of the Combined Gas Law?

mafiozo [28]

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

PV = nRT

and then;

$\frac{P_{1}V_{1} }{T_{1} }$ = $\frac{P_{2}V_{2} }{T_{2} }$

If we cross multiply;

P₁V₁T₂ = P₂V₂T₁

So;

T₁ = $T_{2} \frac{P_{1}V_{1} }{P_{2} V_{2} }$

Also;

V₂ = $V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }$

So from the choices both are correct

3 0

3 years ago

When a 0.245-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.260-g sample

sveticcg [70]

Answer:

The heat of combustion per moles of caffeine is 4220 kJ/mol

Explanation:

Step 1: Data given

⇒ When benzoic acid sample of 0.245 grams is burned the temperature rise is 1.643 °C

⇒ When 0.260 gram of caffeine is burned, the temperature rise is 1.436 °C

⇒ Heat of combustion of benzoic acid = 26.38 kJ/g

Step 2: Calculate the heat released: for combustion of benzoic acid

0.245 g benzoic acid * 26.38 kJ/g = 6.4631 kJ

Step 3: Calculate the heat capacity of the calorimeter:

c = Q/ΔT

Q = 6.4631 kJ / 1.643°C = 3.934 kJ/ °C

Step 4: Calculate moles of a 0.260 g sample of caffeine:

Moles caffeine = Mass caffeine / Molar mass caffeine

0.260 grams/ 194.19 g/mol = 0.0013389 moles

Step 5: Calculate heat released: for combustion of caffeine

Q = c * ΔT

Q = 3.934 kJ/°C * 1.436 °C = 5.65 kJ

Step 6: Calculate the heat of combustion per mole of caffeine

5.65 kJ / 0.0013389 moles = 4219.9 kJ/mol ≈ 4220 kJ/mol

The heat of combustion per moles of caffeine is 4220 kJ/mol

4 0

3 years ago

Bi-S is relatively more stable than bi-n bond. give reasons for the HSAB concept

Rus_ich [418]

Answer:

xhhhvxhxgjhgogftsvicsdgfsytdhdrrygyfhd

Explanation:

ywwgzwu9wu9wsussg the the

5 0

3 years ago

5 Examples of simple salts

kolbaska11 [484]

<h3>Five Examples of Salts </h3>

Sodium Chloride.
Sodium chloride (NaCl) is the most common type of salt in our lives.
Potassium Dichromate. •
Potassium dichromate (K2Cr2O7) is an orange-colored salt composed of potassium, chromium and oxygen.
Calcium Chloride.
Sodium Bisulfate.
Copper Sulfate.

3 0

1 year ago

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O​

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O