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Snezhnost [94]
3 years ago
10

Balance it by oxidation number method:Zn +HNO3----Zn(NO3)2+NO+H2O​

Chemistry
2 answers:
Westkost [7]3 years ago
6 0

Answer:

Your ans is in the picture.

timofeeve [1]3 years ago
3 0

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

Zn +HNO3➔Zn(NO3)2+NO+H2O

step 2: identity undergoing oxidation or reduction

here

Zn➔Zn(NO3)2

Zn is oxidized from 0 to 2 in oxidation no.

HNO3➔NO

N is reduced from 5 to 2 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Zn=0-2=-2=2

in

N=5-2=3

Step 4: Balance it by doing crisscrossed multiplication

we get;

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

step 6:Balance other atoms except H & O

3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O

3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O

finally: balance H

<em><u>3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O</u></em>

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Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: ()zn
Bingel [31]

Based on the chemical equation, to balance the equation we use 2 as a coefficients of HCl on left hand side of reaction.

<h3>What is balanced equation?</h3>

Balanced chemical equations are those equation in which each entities are present in same amount on left side as well as on the right side of the chemical reaction.

Given chemical reaction is:

Zn + HCl → ZnCl₂ + H₂

Above reaction is not balanced equation as number of chlorine and hydrogen atoms are not same, so balanced equation will be:

Zn + 2HCl → ZnCl₂ + H₂

Hence we add 2 as a coefficient of HCl to balance the equation.

To know more about balance equation, visit the below link:
brainly.com/question/26694427

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4 years ago
A substance has a solubility of 350 ppm.how many grams of the substance are present in 1.0l of a saturated solution
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Since the given solubility is 350 ppm, convert it first with fraction of solubility. by dividing the solubility with 10^6
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s = 3.5 x 10^-4
the multiply it to the total solution to calculate the amount of substance present
m = ( 3.5 x 10^-4 ) ( 1.01 )
m = 3.535 x 10^-4 g of the substance present
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3 years ago
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