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inn [45]
3 years ago
7

What element is least likely to be found in nature

Chemistry
1 answer:
Doss [256]3 years ago
5 0

Answer:

uranium, caesium, potassium, beryllium,

Explanation:

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To check that an equation is balanced,count the number of __ on each side of the equation
Jobisdone [24]

Answer:

we count the number of the molecules on each side of the equation.

4 0
3 years ago
Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
3 years ago
Chemical reactions can be detected by changes in____. select all that apply. a)temperature.
Elenna [48]
It would be a, b, and d
4 0
3 years ago
Anything in red is the question
solmaris [256]

Answer:

<em />

  • <em>19. C₂H₂, HF, and H₂O₂ are molecular compounds</em>

<em />

  • <em>20. The formula is CuSO₄. 5H₂O</em>

Explanation:

<u><em>Question 19.</em></u>

The three the chemical formulae in red, C₂H₂, HF, and H₂O₂, represent compounds because a compound is the chemical union of two or more atoms of different kind.

The chemical union is done either by ionic bonds or covalent bonds.

C, H, F, and O are all non-metal elements. Non-metals combine each other through covalent bonds, which is the bond in which electrons are shared to complete the valence shell. Ionic bonds are formed by the electrostatic atraction between ions of different charge and is typical of the bond between a metal and a non-metal.

Thus, all the bonds are covalent and the compounds are molecular compounds.

<em></em>

<u><em>Question 20. </em></u>

<em></em>

You can determine the chemical formula using the molar masses of both Copper(II) sulfate and water.

  • Molar mass of copper(II) sulfate: 159.609 g/mol
  • Molar mass of water: 18.015 g/mol

Call n the number of water molecules in the molecular formula:

  • CuSO₄ . nH₂O

The ratio of water to copper(II) sulfate is:

  • n × molar mass of water / molar mass of the compound
  • n × 18.015 / (n × 18.015 + 159.609) = 36%
  • 18.015n = 0.36(18.015n + 159.609)
  • 18.015n = 6.4854n + 57.45924
  • 11.5296n = 57.45924
  • n = 4.9836 ≈ 5

Therefore, the formula of the hydrate contains 5 molecules of water and it is CuSO₄.5H₂O.

8 0
3 years ago
Please help me asap!
vesna_86 [32]

Answer:

bebe bebe bebe

Explanation:

5 0
3 years ago
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