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Strike441 [17]
3 years ago
14

Use Lewis theory to draw the structure of the compound containing 1 carbon and 4 chlorine atoms. What would you find surrounding

the central atom of this ion?
A. 1 double bond.
B. no double bonds.
C. 2 double bonds.
D. 1 triple bond.
E. none of the above

Chemistry
1 answer:
Nikolay [14]3 years ago
4 0

Answer :  The correct option is, (B) no double bonds.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

As we are given that the structure of the compound containing 1 carbon and 4 chlorine atoms.

Thus, the molecule is, CCl_4

As we know that carbon has '4' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in CCl_4 = 4 + 4(7) = 32

According to Lewis-dot structure, there are 8 number of bonding electrons and 24 number of non-bonding electrons.

From the Lewis-dot structure we conclude that there are 4 single bonds are surrounding the central atom of this ion there is no double or triple bonds are present.

Hence, the correct option is, (B) no double bonds.

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Write the Henderson-Hasselbalch equation for a propanoic acid solution ( CH3CH2CO2H , pKa=4.874 ) using the symbols HA and A− ,
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Answer:

a) [A⁻]/[HA] = 0.227

b) [A⁻]/[HA] = 0.991

c) [A⁻]/[HA] = 2.667

Explanation:

In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:

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pH = pka + Log [A⁻]/[HA]

pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H]

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4.23 = 4.874 + Log [A⁻]/[HA]

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10^{-0.644} = [A⁻]/[HA]

0.227 = [A⁻]/[HA]

  • (b)

4.87 = 4.874 + Log [A⁻]/[HA]

-0.004 = Log [A⁻]/[HA]

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0.426 = Log [A⁻]/[HA]

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2.667 = [A⁻]/[HA]

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