Answer : The correct option is, (B) no double bonds.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
As we are given that the structure of the compound containing 1 carbon and 4 chlorine atoms.
Thus, the molecule is, 
As we know that carbon has '4' valence electrons and chlorine has '7' valence electrons.
Therefore, the total number of valence electrons in
= 4 + 4(7) = 32
According to Lewis-dot structure, there are 8 number of bonding electrons and 24 number of non-bonding electrons.
From the Lewis-dot structure we conclude that there are 4 single bonds are surrounding the central atom of this ion there is no double or triple bonds are present.
Hence, the correct option is, (B) no double bonds.