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Strike441 [17]
3 years ago
14

Use Lewis theory to draw the structure of the compound containing 1 carbon and 4 chlorine atoms. What would you find surrounding

the central atom of this ion?
A. 1 double bond.
B. no double bonds.
C. 2 double bonds.
D. 1 triple bond.
E. none of the above

Chemistry
1 answer:
Nikolay [14]3 years ago
4 0

Answer :  The correct option is, (B) no double bonds.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

As we are given that the structure of the compound containing 1 carbon and 4 chlorine atoms.

Thus, the molecule is, CCl_4

As we know that carbon has '4' valence electrons and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in CCl_4 = 4 + 4(7) = 32

According to Lewis-dot structure, there are 8 number of bonding electrons and 24 number of non-bonding electrons.

From the Lewis-dot structure we conclude that there are 4 single bonds are surrounding the central atom of this ion there is no double or triple bonds are present.

Hence, the correct option is, (B) no double bonds.

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[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

             CO(g) + H2O(g) ↔   CO2(g) + H2(g)

initial     0.5            0.5                    0          0

change  -X              -X                   +X         +X
     
Equ       (0.5-X)       (0.5-X)                     X            X

when Kc = X^2 * (0.5-X)^2

by substitution:

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∴X = 0.26

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4 0
3 years ago
( its supposed to be science but whatever )
lana66690 [7]

Answer:

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Explanation:

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7 0
3 years ago
Read 2 more answers
How many kilograms of oxygen did Samantha need to utilize to react with 36.29 kg of triglycerides (C55H104O6)?
Paraphin [41]

Answer:

105.33Kg of O2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

C55H104O6 + 78O2 —> 55CO2 + 52H2O

Step 2:

Determination of the masses of C55H104O6 and O2 that reacted from the balanced equation.

This is illustrated below:

Molar mass of C55H104O6 = (12x55) + (104x1) + (16x6) = 860g/mol

Mass of C55H104O6 from the balanced equation = 1 x 860 = 860g.

Divide the mass of C55H104O6 by 1000 to express in kg i.e

Mass of C55H104O6 = 860/1000= 0.86Kg

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 78 x 32 = 2496g.

Divide the mass of O2 by 1000 to express in kg i.e

Mass of O2 = 2496/1000 = 2.496kg.

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Step 3:

Determination of the mass of O2 in kg needed to react with 36.29 kg of triglycerides (C55H104O6).

This can be obtained as follow:

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Therefore, 36.29 kg of C55H104O6 will react with = (36.29 x 2.496)/0.86 = 105.33Kg of O2.

Therefore, 105.33Kg of O2 is needed for the reaction.

5 0
2 years ago
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Answer:

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2 years ago
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Identify each description as that of particles of a 1) solid 2) liquid 3) gas __ A. has definite volume but takes the shape of t
Korvikt [17]

Answer:

A.

Liquid

B.

Gas

C.

Gas

D.

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E.

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Explanation:

Solids have definite shape and volume and vibrate around a fixed position. Its relative intermolecular forces are very strong which holds its particles in a fixed position.

Liquids takes the shape of the container, that is no definite shape, has fixed volume and its particles move freely but are still attached to each other due to its mildly strong intermolecular forces.

Gases has no shape nor volume but it is highly compressible while its particles move freely in random paths.

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