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umka2103 [35]
4 years ago
7

Oxygen atoms have six outer electrons Write the symbol for an oxide ion.

Chemistry
1 answer:
Shkiper50 [21]4 years ago
7 0

Answer:

O^{2-} is the symbol for an oxide ion

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How is geologic activity & geologic structure similar?
Sergeeva-Olga [200]

Explanation:

Geological activity determines geological structures. The prevalent types and forms of tectonic working in a place will control the form of structure that can be found in a terrain.

  • In volcanic region, it is common to see volcanic structures of different types such as calderas, strato-volcano etc. These structures are formed by the volcanic activities.
  • Also, in a karst topography, we find sink holes, stalactites and stalagmites etc. due to the nature of the geologic activities going on.
  • Some sedimentary rocks shows cross bedding due to the environment where they form.

So, geologic activities controls the structure found in an area

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3 years ago
Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.
Andru [333]

Answer:

{ \rm{2\: moles  \: of \: sodium \: chlorate = 2 \: moles \: of \: sodium \: choride}} \\ { \rm{10 \: moles \: of \: sodium \: chlorate = ( \frac{10}{2}  \times 2) \: moles}} \\  \\  = { \boxed{ \rm{ \: 10 \: moles \: of \: sodium \: chloride}}} \\

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For which type of titration will the ph be basic at the equivalence point?
Pavel [41]

Answer:

weak acid

Explanation:

3 0
3 years ago
Igneous rocks formed below earths surface
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A) igneous rocks

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3 0
4 years ago
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When 2.714 g of AX (s) dissolves in 127.4 g of water in a coffee-cup calorimeter the temperature rises from 23.3 °C to 37.1 °C.
MakcuM [25]

Answer : The enthalpy change for the solution is 166.34 kJ/mol

Explanation :

First we have to calculate the enthalpy change of the reaction.

Formula used :

\Delta H=mC\Delta T\\\\\Delta H=mC(T_2-T_1)

where,

\Delta H = change in enthalpy = ?

C = heat capacity of water = 4.18J/g.K

m = total mass of sample = 2.174 + 127.4 = 129.6 g

T_1 = initial temperature = 23^oC=273+23=296K

T_2 = final temperature = 37.1^oC=273+37.1=310.1K

Now put all the given values in the above expression, we get:

\Delta H=mC(T_2-T_1)

\Delta H=129.6g\times 4.18J/g.K\times (310.1-296)K=7638.36J

Now we have to calculate the moles of AX added to water.

\text{ Moles of }AX=\frac{\text{ Mass of }AX}{\text{ Molar mass of }AX}=\frac{2.714g}{59.1097g/mole}=0.04592moles

Now we have to calculate the enthalpy change for the solution.

As, 0.04592 moles releases heat = 7638.36 J

So, 1 moles releases heat = \frac{7638.36}{0.04592}=166340.59J=166.34kJ

Therefore, the enthalpy change for the solution is 166.34 kJ/mol

7 0
3 years ago
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