When 70. g of Li3N(s) (molar mass 35 g/mol) reacts with excess H2(g), 8.0 g of LiH(s) is produced. The percent yield is closest
1 answer:
The percent yield is closest to 17%
<h3>How to calculate the percentage yield</h3>The reaction between Li3N(s) and LiH(s) is given as:
Calculate the moles of Li3N
Moles = Mass/Molar mass
Moles = 70/35
Moles = 2 moles
From the reaction you can see that 1 mole of Li3N produce 3 moles of LiH, hence the moles of LiH is 6 moles
Determine the mass of LiH (theoretical yield)
Mass of LiH = 6 * 7.95
Mass of LiH = 47.7g
%yield = actual/theoretical * 100
%yield = 8/47.7 * 100
%yiels = 16.77%
Hence the percent yield is closest to 17%
Learn more on percent yield here: brainly.com/question/25996347
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Answer:
27 min
Explanation:
The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:
Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.
So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min
If Km is a thousand times smaller then [S], then
v = vmax[S]/[S]
v = vmax
vmax = 1.33 μmol/min
For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:
vmax = 1.33/3 = 0.443 μmol/min
Km will still be much smaller then [S], so
v = vmax
v = 0.443 μmol/min
For 12 μmol formed:
0.443 = 12/t
t = 12/0.443
t = 27 min