Question

Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 12,900 kg. The thrust of its engines is 28,000 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.) Calculate the magnitude ofacceleration in the vertical take off from the moon.

Answer 1

Answer:

Acceleration a=0.5 m/s²

Explanation:

Given data

Mass m=12,900 kg=1.29×10⁴kg

Thrust of engine F=28,000 N=2.8×10⁴N

gravitational acceleration g=1.67 m/s²

To find

Acceleration

Solution

As we know  that

$W_{weigth}=mg\\ W=(1.29*10^{4}kg )(1.67m/s^{2} )\\W=21543N$

The net force can be given as

$F_{net}=F_{thrust}-W\\F_{net}=(2.8*10^{4}-21543)N\\ F_{net}=6457 N$

From Newtons second law of motion we know that

$F=ma\\a=F/m\\a=\frac{6457N}{12,900kg}\\ a=0.5m/s^{2}$