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V125BC [204]
3 years ago
7

At constant temperature, a sample of helium at 760. torr in a closed container was compressed from 5.00 l to 3.00 l, with no cha

nge in moles or temperature. what was the new pressure exerted by the helium on its container? 2280 torr 800. torr 15.0 torr 3800 torr 1270 torr
Chemistry
1 answer:
Elden [556K]3 years ago
7 0
<span>At constant temperature and moles, the answer can simply becomes P1V1 = P2V2. The original sample is 760 torr and 5.00 l, and was then compressed to 3.00 l. (760 torr)(5.00 l ) = (3.00 l)(X torr), X = 1270 torr. The new pressure exerted by helium on its container is 1270 torr.</span>
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3 years ago
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Answer:

8.0 mol/L

Explanation:

To do this problem you need to use C₁V₁=C₂V₂. C=concentration and V=volume. (Note: you dont want to use M₁V₁=M₂V₂ because this is measuring mass not concentration).

So, V₁= 1.0L

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you would plug this equation in like this:

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C₁=\frac{(2.0 mol/L)(4.0L)}{1.0L} =8.0 mol/L

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2 years ago
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3 0
2 years ago
What is the remaining concentration of the cation that precipitates first, when the other cation just begins to precipitate? con
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3 years ago
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