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podryga [215]
3 years ago
9

The density of mercury is 13.6 g/cm3, What is its density in mg/mm3?

Chemistry
1 answer:
forsale [732]3 years ago
8 0

Answer:

Density of mercury is 13600 kg

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How many grams of NH3 are needed to provide the same number of molecules as in 0.85 grams of SF6?
solniwko [45]

Above it says the molecular weights are

NH3- 17g/mol and SF6-146 g/mol

Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.


<span><span><span>= 1mole / </span><span>146.048g *</span></span> 0.85g</span>


so we would need 0.00582000438 moles of NH3 to have the same number of molecules.

One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:


<span><span><span>= 17.030519999989988 g / </span><span>mole * </span></span>0.00582000438moles</span>


that equals 0.09911770099 grams.

so 0.09911770099 grams is the answer if you round that you get about 0.1 grams


3 0
3 years ago
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A 30.5 g sample of an alloy at 95.0°C is placed into 49.3 g water at 24.3°C in an insulated coffee cup. The heat capacity of the
user100 [1]

Answer:

0.752 J/g*K

Explanation:

The heat lost by the alloy (which is negative) must be equal to the heat gained by the water and the coffee cup:

-Qa = Qw + Qc

-ma*ca*ΔTa = mw*cw*ΔTw + C*ΔTc

Where, m is the mass, c is the specific heat capacity, C is the heat capacity of the coffee cup, ΔT is the change in temperature, a represents the alloy, and w the water.

The coffee cup has initial temperature equal to the water, then:

-30.5*ca*(31.1 - 95.0) = 49.3*4.184*(31.1 - 24.3) + 9.2*(31.1 - 24.3)

1948.95ca = 1465.20

ca = 0.752 J/g*K

4 0
3 years ago
Which element has a complete valence electron shell? selenium (Se) oxygen (O) fluorine (F) argon (Ar)
kirill115 [55]

Answer:

oxygen (O)

Explanation:

.

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CARBON MOVES THROUGH THE CARBON CYCLE IN ALL OF THE PROCESSES EXCEPT?
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The answer is Decomposition. 
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What is the term called ¨I nutted
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You nutted in her left eye
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