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sasho [114]
3 years ago
14

When a molecule absorbs IR eletromagnetic energy, what are the vibrational modes affected?

Physics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

Stretching vibration and bending vibration

Explanation:

1. Stretching vibration results in the variation of the bond length. There are two types of stretching vibration:

  • In asymmetric bending, bonds move in and out as a result of the vibration.
  • In symmetric bending, bonds move such that the bond length either gets shorter or longer.

2. Bending vibration results in the variation of the bond angle.

These can be grouped into 4 types:

  • Rocking- It is that motion in which two atoms are in the motion like that of the motion of a pendulum of a clock.
  • Scissoring- The motion of to atoms either away from each other or towards each other.
  • Twisting- It is where the motion of the two atoms resembles that of the motion on a treadmill.
  • Wagging- It is the motion in V- shape in the back and forth direction.  
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An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv
konstantin123 [22]

Answer:

8.91 %

Explanation:

Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

[Δg/g × 100 %]² = 79.4644 %²

taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0
3 years ago
PLS HELP!!!- The moon rotates around the Earth every 28 days. What is the frequency of the moon’s revolution?
Naily [24]

Answer: the frequency is every 27.322 days

6 0
3 years ago
HELP!!! ASP EASY QUESTION! WILL GIVE BRAINEST IF U ANSWER!
Harlamova29_29 [7]
I believe the answer is Anther.
The Anther produces the pollen
5 0
3 years ago
A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

200=200ω²

ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
4 years ago
2
timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

a =  \frac{f}{m}

4 0
3 years ago
Read 2 more answers
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