Question

1. A ball is thrown downward with an initial speed of 22 m/s on Earth. a. What is the acceleration of the ball? b. Calculate the displacement during the first 4 s. c. Calculate the time required to reach a speed of 60 m/s.​

Answer 1

Answer:

Explanation:

The acceleration of the ball would be due to the downward force of gravity, 9.8m/s^2. In order to find the displacement given that interval of time, you have to use the corresponding kinematic formula:

$d=v_it+at^2/2$

The initial velocity was given, the time was given, and the acceleration was given. Therefore:

$d=(22m/s)(4s)+(9.8m/s^2)(4s)^2/2$

$d=166.4m$

To find the required time given a desired final velocity, we can use:

$v_f=v_i+at$

$60m/s=22m/s+(9.8m/s^2)(t)$

$38=9.8t$

$t=3.9s$